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This is a tutorial on solving inequalities with absolute value. Detailed solutions and explanations are provided.
Example 1: Solve the inequality.
|x + 2| < 3
Solution to example 1
- The above inequality is solved by writing a double inequality equivalent to the given inequality but without absolute value
- 3 < x + 2 < 3
- Solve the double inequality to obtain
- 5 < x < 1
- The above solution set is written in interval form as follows
(-5 , 1)
Example 2: Solve the inequality.
|- 2x - 4| > 9
Solution to example 2
- Solving the above inequality is equivalent to solving
-2x - 4 > 9 or -2x - 4 < - 9
- Which gives
x < -13 / 2 or x > 5 / 2
- The above solution set is written in interval form as follows
(-inf , -13 / 2) U (5 / 2 , + inf)
Example 3: Solve the inequality.
x + 2 < |x2 - 4|
Solution to example 3
- Condition 1 - For x2 - 4 > = 0, or x in the interval (-inf , -2] U [2 , +inf),
we can write
|x2 - 4| = x2 - 4
- Substitute the expression with the absolute value in the given inequality and solve
x + 2 < x2 - 4
x2 - x - 6 > 0
- The solution set to above inequality is given by the interval
(-inf , -2) U (3 , +inf)
- The intersection of intervals(-inf , -2] U [2 , +inf) and (-inf , -2) U (3 , +inf) gives the solution set
(-inf , -2) U (3 , +inf)
Condition 2 - For x2 - 4 < 0, or x in the interval (-2 , 2), we can write
|x2 - 4| = -(x2 - 4)
- Substitute the expression with the absolute value in the given inequality and solve
x + 2 < -(x2 - 4)
x2 + x - 2 < 0
- The solution set to above inequatlity is given by the intersection of the intervals (-2 , 1) and (-2 , 2)
(-2 , 1)
- Conclusion: The solution set to the given inequality is
(-inf, -2) U (-2 , 1) U (3 , +inf)
Check the above answer to the inequality graphically.(see graph below).
More references and links on how to Solve Equations, Systems of Equations and Inequalities.
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