Radius of Circumcircle

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Given a triangle with vertices A, B and C, find a formula for the radius R of thecircumcircle .

angle BOC is twice angle BAC since they intercept the same chord BC but BOC is a central angle Euclid's Elements, Book III, Proposition 20 and central and inscribed angles. In triangle BOC, BM = MC. Which leads to angle BOM = angle MOC.
Which leads to saying that angle BOM = angle MOC = angle A. In the triangle BOM,
sin(BOM) = BM / OB

BM =BC/2
Which leads to:

sin(BOM) = BC / (2*OB)

angle BOM = angle A and OB is the radius R of the circle.
sin(A) = BC / (2R)
2R = BC / sin(A)
and now using the sine law, we have

2R = BC / sin(A) = AC / sin(B) = AB / sin(C)

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Updated: 18 January 2006 (A Dendane)