When a transversal line intersects two parallel lines, it creates specific angle relationships that are always consistent. This tutorial explores these relationships with diagrams, definitions, and solved examples.
You may also want to solve additional problems on angles in parallel lines and transversals.
When two parallel lines are cut by a transversal, the angles in matching corners are called corresponding angles and are congruent:
Thus:
\[ m\angle a = m\angle a', \quad m\angle b = m\angle b', \quad m\angle c = m\angle c', \quad m\angle d = m\angle d' \]
Alternate interior angles lie on opposite sides of the transversal and between the two parallel lines. They are always congruent:
Thus:
\[ m\angle d = m\angle b', \quad m\angle c = m\angle a' \]
Alternate exterior angles lie on opposite sides of the transversal and outside the two parallel lines. They are always congruent:
Thus:
\[ m\angle a = m\angle c', \quad m\angle b = m\angle d' \]
Given that \( L_1 \parallel L_2 \), find the measures of angles \( b, c, d, e, f, g, \) and \( h \).
In the figure below, \( L_1 \parallel L_2 \) and \( L_3 \parallel L_4 \), forming a parallelogram. Show that:
Given: \( m\angle a = 74^\circ \), \( L_1 \parallel L_2 \)
Step 1: \( \angle a \) and \( \angle b \) are supplementary angles (linear pair):
\[ m\angle a + m\angle b = 180^\circ \Rightarrow 74^\circ + m\angle b = 180^\circ \Rightarrow m\angle b = 106^\circ \]
Step 2: \( \angle b \) and \( \angle d \) are vertical angles, so:
\[ m\angle d = m\angle b = 106^\circ \]
Step 3: \( \angle a \) and \( \angle c \) are vertical angles, so:
\[ m\angle c = m\angle a = 74^\circ \]
Step 4: Using corresponding angles (since \( L_1 \parallel L_2 \)):
\[ m\angle f = m\angle a = 74^\circ,\quad m\angle e = m\angle b = 106^\circ \]
\[ m\angle g = m\angle c = 74^\circ,\quad m\angle h = m\angle d = 106^\circ \]
Answer: \( \angle b = 106^\circ, \angle c = 74^\circ, \angle d = 106^\circ, \angle e = 106^\circ, \angle f = 74^\circ, \angle g = 74^\circ, \angle h = 106^\circ \)
Part 1: Show opposite angles are congruent
Since \( L_1 \parallel L_2 \) and \( L_3 \) is a transversal, corresponding angles give:
\[ m\angle d = m\angle h \]
Since \( L_1 \parallel L_2 \) and \( L_4 \) is a transversal, corresponding angles give:
\[ m\angle d' = m\angle h' \]
Since \( L_3 \parallel L_4 \) and \( L_1 \) is a transversal, corresponding angles give:
\[ m\angle d = m\angle d' \]
Since \( L_3 \parallel L_4 \) and \( L_2 \) is a transversal, corresponding angles give:
\[ m\angle h = m\angle h' \]
Thus \( m\angle d = m\angle h' \). But \( \angle h' \) and \( \angle e' \) are vertical angles, so \( m\angle h' = m\angle e' \). Therefore:
\[ m\angle d = m\angle e' \]
Similarly, \( m\angle g = m\angle a' \). Since \( \angle a' \) and \( \angle c' \) are vertical angles, \( m\angle a' = m\angle c' \), so:
\[ m\angle g = m\angle c' \]
Part 2: Show consecutive angles are supplementary
Angles \( \angle a \) and \( \angle d \) are supplementary (linear pair). But \( \angle a \) and \( \angle g \) are corresponding angles (since \( L_1 \parallel L_2 \)), so \( m\angle a = m\angle g \). Thus:
\[ m\angle d + m\angle g = 180^\circ \quad \text{(supplementary)} \]
Similarly, \( \angle b' \) and \( \angle c' \) are supplementary, and \( \angle b' \) and \( \angle e' \) are corresponding angles, so \( m\angle b' = m\angle e' \). Thus:
\[ m\angle c' + m\angle e' = 180^\circ \quad \text{(supplementary)} \]
More practice problems on parallel lines and transversals are available.