Problem 1:In the isosceles triangle ABC, BA and BC are congruent. M and N are points on AC such that MA is congruent to MB and NB is congruent to NC. Show that triangles AMB and CNB are congruent.
Solution to Problem 1:
 Since triangle ABC is isosceles and BA and BC are congruent then angles BAM and BCN are congruent.
 Also since MA is congruent to MB, then AMB is an isosceles triangle and angles BAM and ABM are congruent. NB and NC are also congruent; CNB is an isosceles triangle and angles CBN and BCN are congruent. In fact all four angles BAM, ABM, CBN and BCN are congruent. Comparing triangles BAM and CNB, they have corresponding sides AB and BC congruent, corresponding angles BAM and BCN congruent and corresponding angles ABM and CBN congruent. These two triangles are therefore congruent. This is the ASA congruent case.
Problem 2: ABCD is a parallelogram and BEFC is a square. Show that triangles ABE and DCF are congruent.
Solution to Problem 2:
 In the parallelogram ABCD, BA is congruent to CD. In the square BEFC, EB is congruent to FC. Since EB is parallel to FC and BA is parallel to CD then angles EBA and FCD are congruent. Comparing triangles ABE and DCF: angle EBA included between EB and BA in triangle ABE is congruent to angles FCD included between sides FC and CD. EB is congruent to FC and BA is congruent to CD. These two triangles are congruent. It is the SAS congruent case.
Problem 3: ABCD is a square. C' is a point on BA and B' is a point on AD such that BB' and CC'are perpendicular. Show that AB'B and BC'C are congruent.
Solution to Problem 3:
 Since ABCD is a square angles CBC' and BAB' are right angles and therefore congruent. Also side BA is congruent to side BC. BC and AD are parallel and BB' is a transverse, therefore angles OBC and BB'A are interior alternate angles and are congruent.
 Since CC' and BB' are perpendicular, then triangle CBO is rectangle at point O and therefore
size of angle OBC + size of angle BCO = 90 degrees
 ABB' is also a right triangle and therefore
size of angle ABB' + size of angle BB'A = 90 degrees
 Combine the above equations with the fact that angles OBC and BB'A are congruent, we can conclude that
size of angle ABB' = size of angle BCC'
 Triangles AB'B and BC'C have side BC congruent to side BA; angle BCC' congruent to angle ABB' and angle BAB' congruent to angle CBC' are congruent. The two triangles are congruent. This is the ASA congruent case.
Problem 4: ABC is a triangle and M is the midpoint of AC. I and J are points on BM such that AI and CJ are perpendicular to BM. Show that triangles AIM and CJM are congruent.
Solution to Problem 4:
 Since M is the midpoint of AC then AM is congruent to MC. AI and CJ are perpendicular to the same line BM and are therefore parallel with CA as the transverse. Angles MAI and MCJ are interior alternate angles and therefore congruent. Angles AMI and JMC are vertical angles and therefore congruent. Triangles AIM and CJM have one congruent side between two congruent angles and are therefore congruent. This is the ASA congruent case.
Problem 5: ABC is an isosceles triangle with BA and BC congruent. Point K is on AB and point L is on BC. Both KK' and LL' are perpendicular to AC. Segments KK' and LL' are congruent. Show that KK'M and LL'M are congruent.
Solution to Problem 5:
 KK' and LL' are perpendicular to the same line AC and are therefore parallel to each other. KL is transverse to these two lines and K'KM and L'LM are interior alternate angles and therefore congruent. Angles KK'M and LL'M are congruent since the size of each is 90 degrees. The two triangles KK'M and LL'M have one corresponding congruent side between two congruent angles and are therefor congruent.
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