# Find Domain and Range of Arcsine Functions

 Questions on how to find domain and range of arcsine functions. Theorems 1.     y = arcsin x     is equivalent to     sin y = x with     -1 ≤ x ≤ 1     and     - pi / 2 ≤ y ≤ pi / 2 Question 1: Find the domain and range of y = arcsin(x - 1) Solution to question 1: 1. Domain: To find the domain of the above function, we need to impose a condition on the argument (x - 1) according to the domain of arcsin(x) which is -1 ≤ x ≤ 1 . Hence -1 ≤ (x - 1) ≤ 1 solve to obtain domain as: 0 ≤ x ≤ 2 which as expected means that the graph of y = arcsin(x - 1) is that of y = arcsin(x) shifted one unit to the right. 2. Range: A shift to the right does not affect the range. Hence the range of y = arcsin(x - 1) is the same as the range of arcsin(x) which is - pi / 2 ≤ y ≤ pi / 2 Question 2: Find the domain and range of y = - arcsin(x + 2) Solution to question 2: 1. Domain: To find the domain of the above function, we need to impose a condition on the argument (x + 2) according to the domain of arcsin(x) which is -1 ≤ x ≤ 1 . Hence -1 ≤ (x + 2) ≤ 1 solve to obatain domain as: - 3 ≤ x ≤ - 1 which as expected means that the graph of y = arcsin(x + 2) is that of y = arcsin(x) shifted two units to the left. 2. Range: The range of arcsin(x + 2) is the same as the range of arcsin(x) which is - pi / 2 ≤ y ≤ pi / 2. Hence we can write - pi / 2 ≤ arcsin(x + 2) ≤ pi / 2 We now multiply all terms of the above inequality by - 1 and invert the inequality symbols pi / 2 ≥ - arcsin(x + 2) ≥ - pi / 2 Which is equivalent to - pi / 2 ≤ - arcsin(x + 2)≤ pi / 2 which gives the range of y = - arcsin(x + 2) as the interval [- pi / 2 , pi / 2] Question 3: Find the domain and range of y = -2 arcsin(3 x - 1) Solution to question 3: 1. Domain: To find the domain, we need to impose the following condition -1 ≤ (3 x - 1) ≤ 1 solve to obtain domain as: 0 ≤ x ≤ 2 / 3 2. Range: The range of arcsin(3x - 1) is the same as the range of arcsin(x) which is - pi / 2 ≤ y ≤ pi / 2. Hence we can write - pi / 2 ≤ arcsin(3x - 1) ≤ pi / 2 We now multiply all terms of the above inequality by - 2 and invert the inequality symbols pi ≥ - 2 arcsin(3x - 1) ≥ - pi which gives the range of y = - 2 arcsin(3x - 1) as the interval [- pi , pi] Question 4: Find the domain and range of y = 4 arcsin( -2(x - 1) ) - pi/2 Solution to question 4: 1. Domain: To find the domain, we need to impose the following condition -1 ≤ -2(x - 1) ≤ 1 solve to obtain domain as: 1 / 2 ≤ x ≤ 3 / 2 2. Range: The range of arcsin(-2(x - 1)) is the same as the range of arcsin(x) which is - pi / 2 ≤ y ≤ pi / 2. Hence we can write - pi / 2 ≤ arcsin(-2(x - 1)) ≤ pi / 2 We now multiply all terms of the above inequality by 4 -2 pi ≥ 4 arcsin(-2(x - 1)) ≥ 2 pi We now subtract - pi/2 from all terms of the above inequality. - 5 pi / 2 ≥ 4 arcsin(-2(x - 1)) ≥ 3 pi / 2 which gives the range of y = 4 arcsin(-2(x - 1)) - pi / 2 as the interval [- 5 pi / 2 , 3 pi / 2]