Find Derivative of y = x^{ x}
A calculus tutorial on how to find the first derivative of y = x^{ x} for x > 0.
Note that the function defined by y = x^{ x} is neither a power function of the form x^{ k} nor an exponential function of the form b^{ x} and the formulas of Differentiation of these functions cannot be used. We need to find another method to find the first derivative of the above function.
If y = x^{ x} and x > 0 then ln y = ln (x^{ x})
Use properties of logarithmic functions to expand the right side of the above equation as follows.
ln y = x ln x
We now differentiate both sides with respect to x, using chain rule on the left side and the product rule on the right.
y '(1 / y) = ln x + x(1 / x) = ln x + 1 , where y ' = dy/dx
Multiply both sides by y
y ' = (ln x + 1)y
Substitute y by x^{ x} to obtain
y ' = (ln x + 1)x^{ x}
Exercise: Find the first derivative of y = x^{x  2}
Answer to Above Exercise: y ' = x^{ x  3} (x ln x + x  2)
More on differentiation and derivatives 
