# Derivative, Maximum, Minimum of Quadratic Functions

Differentiation is used to analyze the properties such as intervals of increase, decrease, local maximum, local minimum of quadratic functions.

We shall consider two forms of the quadratic functions. ## A - General form.
Quadratic functions in their general form are written as
f(x) = a x^{ 2} + b x + cwhere a, b and c are real numbers such that a not equal to zero. The first derivative of f is given by f ' (x) = 2 a x + b Let us analyze the sign of f' and hence determine any maximum or minimum point and the intervals of increase and decrease. f '(x) is positive if 2 a x + b > 0 add -b to both sides of the inequality to obtain 2 a x > -b We now need to consider two cases and continue solving the inequality above. case 1: a > 0 We divide both sides of the inequality by 2 a and obtain x > - b / 2a We now use a table to analyze the sign of f ' and whether f is increasing over a given interval. The quadratic function with a > 0 has a minimum point at (-b/2a , f(-b/2a)) and the function is decreasing on the interval (-infinity , -b / 2a) and increasing over the interval (-b / 2a , + infinity). case 2: a < 0 We divide both sides of the inequality by 2 a but because a is less than 0, we need to change the symbol of inequality x < - b / 2a We now analyze the sign of f ' using the table below The quadratic function with a < 0 has a maximum point at (-b/2a , f(-b/2a)) and the function is increasing on the interval (-infinity , -b / 2a) and decreasing over the interval (-b / 2a , + infinity).
## B - Vertex form.Quadratic functions in their vertex form are written asf(x) = a (x - h)^{ 2} + kwhere a, h and k are real numbers with a not equal to zero. The first derivative of f is given by f '(x) = 2 a (x - h) We analyze the sign of f' using a table. f '(x) is positive if a (x - h) > 0 We need to consider two cases again and continue solving the inequality above. case 1: a > 0 We divide both sides of the inequality by a and solve the inequality x > h The table below is used to analyze the sign of f '. The quadratic function with a > 0 has a minimum at the point (h , k) and it is decreasing on the interval (-infinity , h) and increasing over the interval (h , + infinity). case 2: a < 0 We divide both sides of the inequality by a but we need to change the symbol of inequality because a is less than 0. x < h We analyze the sign of f ' using the table below The quadratic function with a < 0 has a maximum point at (h , k) and the function is increasing on the interval (-infinity , h) and decreasing over the interval (h , + infinity).
^{ 2} - 8 x + 1
Solution to Example 1.-
We first find the derivative
f ' (x) = 4 x - 8 f ' (x) changes sign at x = 8 / 4 = 2. The leading coefficient a is positive hence f has a minimum at (2 , f(2)) = (2 , -7) and f is decreasing on (-infinity , 2) and increasing on (2 , + infinity). See graph below to confirm the result obtained by calculations.
^{ 2} + 1
Solution to Example 2.-
The derivative is given by
f '(x) = - 2 (x + 3) f '(x) changes sign at x = -3 . The leading coefficient a is negative hence f has a maximum at (-3 , 1) and f is increasing on (-infinity , -3) and decreasing on (-3 , + infinity). See graph below of f below.
applications of differentiation |