where n = 1 , 2 , 3 , ... and T is the period of function f(t). an and bn are called Fourier coefficients and are given by
Example : Find the Fourier series of the periodic function f(t) defined by
Solution to the above example
Coefficient a0 is given by
Coefficients an is given by
And coefficients bn is given by
A computation of the above coefficients gives
a0 = 0 , an = 0 and bn = [ 2 / (n*pi) ] [ 1 - cos (n pi) ]
Note that cos (n pi) may be written as
cos (n pi) = (-1)n
and that bn = 0 whenever n is even.
The given function f(t) has the following Fourier series
Now below is an applet that may be used to explore the Fourier series of f(t) defined above
click on the button above "click here to start" and MAXIMIZE the window obtained.
1 - When the applet is first started, only f(t) (in blue) is displayed.
2 - Use the slider N to increases the number of terms in the series and see how the Fourier series (in red) gives a close approximation to function f(t) as the number of terms N in the series increases. Note also how the amplitude and period of the harmonics (in black) change with N. Although Fourier series are infinite, only few harmonics (terms in the series) are enough for a good approximation of f(t).
3 - You may zoom in and out and see closely what happens where f(t) is discontinuous.
4 - You may use the slider b to change the period of function f(t). Period T is given by T = 2 pi / b.