Polynomial Graphs Questions with Solutions

How to use the properties of the polynomial graphs to identify polynomials. Grade 12 math questions with detailed solutions and graphical interpretations are presented.

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Questions on Graphs of Polynomials

  1. Question 1
    Give four different reasons why the graph below cannot possibly be the graph of the polynomial function \( p(x) = x^4-x^2+1 \).

    graph of polynomial in question 1.


    Solution
    The four reasons are:
    1) The given polynomial function is even and therefore its graph must be symmetric with respect to the y axis. The given graph is not symmetric with respect to the y axis.
    2) The given polynomial function does not have real zeros (discriminant = -3 : negative). The given graph has x intercepts which must corresponds to real zeros.
    3) The y intercept calculated using p(x)( p(0) = 04 - 02 + 1 = 1) is positive. The y intercept of the graph is negative.
    4) Having a leading coefficient ( = 1) positive and an even degree ( = 4), the polynomial must have a graph with the right and left both rising. In the given graph, they are both falling.

  2. Question 2
    Match the polynomial functions to their graphs where all x intercepts are shown.
    $$f(x) = (x+1)(x-1)^2(x+2)^2$$ $$g(x) = -(x+1)(x-1)^4$$ $$h(x) = (x+1)(x-1)^3(x-3)$$ $$i(x) = (x+1)^2(x-2)^3$$ $$j(x) = (x+1)^2(1-x)(x-2)^2$$ $$k(x) =-(x+1)^2(x-1)^2(x-3)$$

    graph of polynomial in question 2.


    Solution
    According to their equations, all 6 given polynomial functions are of degree 5. However their leading coefficients are of different signs. We classify the 6 polynomials into 2 groups: I and II
    Group I - Given polynomials with positive leading coefficients
    f(x) = (x + 1)(x - 1)2(x + 2)2
    h(x) = (x + 1)(x - 1)3(x - 3)
    i(x) = (x + 1)2(x - 2)3
    Having degree 5 (odd) and leading coefficients positive, each of the graphs of the above polynomials (f, h and i) has the following graphical properties:
    as   x ____> ∞   ,   y ____> ∞   (the right hand side of the graphs rises)
    as   x ____> - ∞   y ,   ____> - ∞   (the left hand side of the graph falls)
    The given graphs in parts a) c) and e) have the above properties with different x intercepts and their multiplicities. Hence
    Polynomial f(x) = (x + 1)(x - 1)2(x + 2)2 has a zero of multiplicity 1 at x = -1 , a zero of multiplicity 2 at x = 1 and a zero of multiplicity 2 at x = - 2 and should correspond to the graph in part e).
    Polynomial h(x) = (x + 1)(x - 1)3(x - 3) has a zero of multiplicity 1 at x = -1 , a zero of multiplicity 3 at x = 1 and a zero of multiplicity 1 at x = 3 and should correspond to the graph in part a).
    Polynomial i(x) = (x + 1)2(x - 2)3 has a zero of multiplicity 2 at x = -1 and a zero of multiplicity 3 at x = 2 and should correspond to the graph in part c).
    Group II - Given polynomials with negative leading coefficients
    The polynomial functions g, j and k, when expanded, have leading coefficients that are negative.
    g(x) = - (x + 1)(x - 1)4
    j(x) = (x + 1)2(1 - x)(x - 2)2
    k(x) = - (x + 1)2(x - 1)2(x - 3)
    Having degree 5 (odd) and leading coefficients negative, each of the graphs of the above polynomials (g, j and k) has the following graphical properties:
    as   x ____> ∞   ,   y ____> - ∞   (the right hand side of the graphs falls)
    as   x ____> - ∞   y ,   ____> ∞   (the left hand side of the graph rises)
    The given graphs in parts b) d) and f) have the above properties with different x intercepts and their multiplicities. Hence
    Polynomial g(x) = - (x + 1)(x - 1)4 has a zero of multiplicity 1 at x = -1 , a zero of multiplicity 4 at x = 1 and should correspond to the graph in part f).
    Polynomial j(x) = (x + 1)2(1 - x)(x - 2)2 has a zero of multiplicity 2 at x = -1 , a zero of multiplicity 1 at x = 1 and a zero of multiplicity 2 at x = 2 and should correspond to the graph in part d).
    Polynomial k(x) = - (x + 1)2(x - 1)2(x - 3) has a zero of multiplicity 2 at x = -1 , a zero of multiplicity 2 at x = 1 and a zero of multiplicity 1 at x = 3 and should correspond to the graph in part b).

References and Links

High School Math (Grades 10, 11 and 12) - Free Questions and Problems With Answers
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