# Intermediate Algebra Problems With Answers - Sample 5 - Scientific Notation

A set of intermediate algebra problems, related to scientific notation, with answers, are presented. The solutions are at the bottom of the page.

 Review: A number x is written in scientific notation when it is written in the form: x = a × 10 N with 1 ≤ |a| < 10 and N is an integer. Convert from decimal notation to scientific notation. a) 234 b) 0.000052 c) -220,000 d) -0.00000000000000182 Convert from scientific to decimal notation. a) 1.01 × 10 2 b) 8.2 × 10 -6 c) 3.456 × 10 10 d) -1.2 × 10 -8 Perform the multiplication and write the result in scientific notation. a) (5 × 10 2)(7 × 10 5) b) (1.2 × 10 -6)(3.5 × 10 14) c) (-4.5 × 10 -7)(8.62 × 10 10) d) (-7.2 × 10 -6)(0.00039) Perform the division and write the result in scientific notation. a) (4 × 10 13) / (5 × 10 -4) b) 0.000012 / (2.4 × 10 -8) c) (-1.2 × 10 -6) / (1.5 × 10 -10) d) 0.00000065 / 0.000013 Evaluate and express in scientific notation. a) (1.3 × 10 -6) 2 b) (1.5 × 10 -8) 2(2.1 × 10 5) c) [ (1.144 × 10 2)(6 × 10 7) ] / (2.2 × 10 4) d) [ (0.00001)(2,500) ] / [ (0.0003)(150,000) ] Evaluate in scientific notation. a) The diameter of an atom: 0.0000000000001 meter b) diameter of earth = 12,756,000 meters c) 1 billion: 1000,0000,000 d) 1 micron: 0.000001 meter e) 1 trillion: 1000,000,000,000 f) Diameter of earth / diameter of atom g) Speed of light: 300,000,000 m/sec h) Distance travelled by light in one year. Answers to the Above Questions a) 234 = 2.34× 10 2 b) 0.000052 = 5.2× 10 -5 c) -220,000 = -2.2× 10 5 d) -0.00000000000000182 = -1.82× 10 -15 a) 1.01 × 10 2 = 101 b) 8.2 × 10 -6 = 0.0000082 c) 3.456 × 10 10 = 34560000000 d) -1.2 × 10 -8 = -0.000000012 a) (5 × 10 2)(7 × 10 5) = (5 × 7)(10 2 × 10 5) = 35 × 10 7 = 3.5 × 10 8 b) (1.2 × 10 -6)(3.5 × 10 14) = (1.2×3.5)(10 -6 × 10 14) = 4.2 × 10 8 c) (- 4.5 × 10 -7)(8.62 × 10 10) = (- 4.5 × 8.62)(10 -7 × 10 10) = - 38.79 × 10 3 = - 3.879 × 10 4 d) (- 7.2 × 10 -6)(0.00039) = (- 7.2 × 10 -6)(3.9 × 10 -4) = (- 7.2 × 3.9)(10 -6 × 10 -4) = - 28.08 × 10 -10 = - 2.808 × 10 -9 a) (4 × 10 13) / (5 × 10 -4) = (4/5)(10 13 / 10 -4) = 0.8 × 10 17 = 8.0 × 10 16 b) 0.000012 / (2.4 × 10 -8) = (0.000012 / 2.4)(1 / 10 -8) = (0.000005)(1 / 10 -8) = (5.0 × 10 -6)(10 8) = 5.0 × 10 2 c) (-1.2 × 10 -6) / (1.5 × 10 -10) = (-1.2 / 1.5)(10 -6 / 10 -10) = -0.8 × 10 4 = -8.0 × 10 3 d) 0.00000065 / 0.000013 = 0.05 = 5.0 × 10 -2 a) (1.3 × 10 -6) 2 = (1.3) 2 (10 -6) 2 = 1.69 × 10 -12 b) (1.5 × 10 -8) 2(2.1 × 10 5) = 1.5 2 (10 -8) 2 (2.1 × 10 5) = (2.25 × 10 -16)(2.1 × 10 5) = 4.725 × 10 -11 c) [ (1.144 × 10 2)(6 × 10 7) ] / (2.2 × 10 4) = (6.864 × 10 9) / (2.2 × 10 4) = (6.864 / 2.2) (10 9 / 10 4) = 3.12 × 10 5 d) [ (0.00001)(2,500) ] / [ (0.0003)(150,000) ] = 0.025 / 45 = 0.000555 = 5.6 × 10 -4 a) The diameter of an atom: 0.0000000001 meter = 1.0 × 10 -9 meter b) diameter of earth = 12,756,000 meters = 1.2756 × 10 7 meters c) 1 billion: 1000,0000,000 = 1.0 × 10 9 d) 1 micron: 0.000001 meter = 1.0 × 10 -6 e) 1 trillion: 1000,000,000,000 = 1.0 × 10 12 f) Diameter of earth / diameter of atom = 1.2756 × 10 7 / 1.0 × 10 -9 = 1.2756 × 10 16 g) Speed of light: 300,000,000 meters per second = 3.0 10 8 m/s h) Distance travelled by light in one year: There are (365 * 24 * 60 * 60) = 3.1536 × 10 7 seconds in one year. Distance travelled by light in one year = time * speed of light = (3.1536 × 10 7)(3.0 10 8) = 9.4608 × 10 15 meters = 9.4608 × 10 12 kilometers Algebra Questions and problems More ACT, SAT and Compass practice