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Example 1
Solve quadratic equations by first expanding and then factoring.
What are the real roots of the equation $(x+3)(x−1)=-4$?
- $-3$ and $1$
- $-7$ and $-3$
- $-1$
- $1$
- $3$ and $1$
Solution
- We first need to expand the left side of the given equation and write in quadratic standard form (left side equal to zero)
$(x+3)(x−1)=-4$
$x^2-x+3x-3=-4$
$x^2+2x+1=0$
- We now factor the above equation
$(x+1)^2=0$
- Solve for $x$
$x=-1$
Answer C
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