Example Question 5

Example corresponding to question 5 in algebra_4.

Example 1


$(- \dfrac{2}{5})(x+3)(-30)=?$

  1. $-12x+36$


  2. $6x-18$


  3. $-12x-36$


  4. $60(x+3)$


  5. $12x+36$

Solution


  1. We need to simplify the given expression by first rewriting the given expression as follows

    $(-\dfrac{2}{5})(x+3)(-30)=(-\dfrac{2}{5})(-30)(x+3)$

  2. We simplify the term $(-\dfrac{2}{5})(-30)$ as follows

    $(-\dfrac{2}{5})(-30)=(\dfrac{60}{5})=12$

  3. Substitute in the main expression and simplify. Hence

    $(-\dfrac{2}{5})(x+3)(-30)= 12(x+3) = 12x + 36$

    Answer E