Example Question 8

Example corresponding to question 8 in algebra_4.

Example 1


If $3v=h+9$ and $w=\dfrac{1}{3}h + 5$, then $w=$

  1. $v+2$


  2. $v-2$


  3. $3v+5$


  4. $2v-1$
  5. $0$

Solution


  1. From the 5 possible answers, we need to express $w$ in terms of $v$. We first express $h$ in terms of $v$ by solving $3v=h+9$ for $h$.

    $3v=h+9$ gives $h=3v-9$

  2. We now substitute $h$ by 3v-9 in the second equation $w=\dfrac{1}{3}h + 5$ as follows

    $w=\dfrac{1}{3}(3v-9) + 5$



  3. Simplify

    $w=\dfrac{1}{3}\cdot3v-\dfrac{1}{3}\cdot9 + 5$


    $w=v-3 + 5$


    $w=v+2$


    Answer A