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Review
Let p(x) be a polynomial function with real coefficients. If p(s) = 0
- s is a zero for the polynomial function p(x).
- s is a solution to the equation p(x) = 0
- x - s is a factor of p(x).
- The point (s , 0) is an x intercept of the graph of p(x).
Example: let p(x) = x3 - 2·x2 + 2·x - 4
- p(2) = 23 - 2*22 + 2*2 - 4
= 8 - 8 + 4 - 4
= 0
2 is a zero of p(x).
- x = 2 is a solution of p(x) = 0
- p(x) can be written in factored form as
p(x) =(x - 2)·(x2 + 2)
- The graph of p(x) below shows an x intercept at x = 2.
TUTORIAL
Example - Problem 1: The graph below is that of a polynomial function p(x) with real coefficients. The degree of p(x) is 3 and the zeros are assumed to be integers. Find p(x).
Solution to Problem 1:
- The graph has 2 x intercepts: -1 and 2. The x intercept at -1 is of multiplicity 2. p(x) can be written as follows
p(x) = a(x + 1)2(x - 2) , a is any real constant not equal to zero.
- To find a we need to use more information in the graph. The y intercept is at (0 , -2), which means that p(0) = -2
- Solve the above equation for a to obtain
- p(x) is given by
Example - Problem 2: A polynomial function p(x) with real coefficients and of degree 5 has the zeros: -1, 2(with multiplicity 2) , 0 and 1. p(3) = -12.
Find p(x).
Solution to Problem 2:
- p(x) can be written as follows
p(x) = ax(x + 1)(x - 2)2(x - 1) , a is any real constant not equal to zero.
- p(3) = -12 gives the following equation in a.
a(3)(3 + 1)(3 - 2)2(3 - 1) = -12
- Solve the above equation for a to obtain
- p(x) is given by
p(x) = -0.5x(x + 1)(x - 2)2(x - 1)
- The graph of p(x) is shown below.
Check the intercepts and the point (3 , -12) on the graph of p(x) found above.
More references and links to polynomial functions.
Factor Polynomials.
Polynomial Functions.
Multiplicity of Zeros and Graphs Polynomials.
Find Zeros of Polynomial Functions - Problems
Graphs of Polynomial Functions - Self Test.
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