|Answers to Above Questions|
- Since x = 0 is a repeated zero or zero of multiplicity 3, then the the graph cuts the x axis at one point.
An x intercept at x = -2 means that Since x + 2 is a factor of the given polynomial. Hence the given polynomial can be written as: f(x) = (x + 2)(x2 + 3x + 1). Find the other zero, which give the two other x intercpets, by solving the equation x2 + 3x + 1 = 0. The solutions are: x = -3/2 + SQRT(5) / 2 and x = -3/2 - SQRT(5) / 2.
- Use the y intercept to find a = 1 and then proceed in the same way as was done in question 2 above to find the other 2 x intercepts: 3/2 - SQRT(5) / 2 and 3/2 + SQRT(5) / 2
Factor f as follows: f(x) = (x + 1)(x2 + x + 1). In solving the equation x2 + x + 1 = 0, the zeros are complex numbers and therefore do not show as x intercepts.
More references and links to polynomial functions.