Angle \( \theta \) with initial side on the positive x axis and terminal side OM is shown below. It is an angle in standard position.
The cosecant function \( csc (\theta) \) is defined as
\( \csc(\theta) = \dfrac{r}{y} \) , where \( r \) is the distance from O to M and is given by \( r = \sqrt{x^2+y^2} \).
An examination of the definiton of the cosecant gives a relationship between \( csc (\theta) \) and \( sin (\theta) \) as follows
\( \csc(\theta) = \dfrac{r}{y} = \dfrac{1}{\sin(\theta)}\)
Note that
1) \( \csc(\theta+2\pi) = \dfrac{1}{\sin(\theta+2\pi)} = \dfrac{1}{\sin(\theta)}= \csc(\theta)\)
and therefore \( \csc(\theta) \) is a periodic function whose period is equal to \( 2\pi \).
2) \( \csc(-\theta) = \dfrac{1}{\sin(-\theta)} = \dfrac{1}{-\sin(\theta)} = - \dfrac{1}{\sin(\theta)} = - \csc(\theta)\)
and therefore \( \csc(\theta) \) is an odd function and its graph is symmetric with respect to the origin of a rectangular system of coordinates.
We now use a unit circle to find \( \sin(\theta)\) and hence \( \csc(\theta)\) over one period extending from \( \theta = 0 \) to \( \theta = 2\pi \).
We know from the sine and cosine functions that the x and y coordinates on a unit circle gives the values of \( \sin(\theta)\) and \( \cos(\theta)\) as shown below.
Let us now put the values of the quadrantal angles angles \( 0, \dfrac{\pi}{2} , \pi , \dfrac{3\pi}{2} , 2\pi \) and the corresponding values of \( \sin(\theta)\) and \( \csc (\theta) = \dfrac{1}{\sin (\theta)} \) on a table as shown below.
| \( \theta \) | \( \sin(\theta) \) | \( \csc (\theta) = \dfrac{1}{\sin (\theta)} \) |
| \( 0 \) | \( 0 \) | undefined |
| \( \dfrac{\pi}{2} \) | \( 1 \) | 1 |
| \( \pi \) | \( 0 \) | undefined |
| \( \dfrac{3\pi}{2} \) | \( -1 \) | -1 |
| \( 2\pi \) | \( 0 \) | undefined |
| \( \theta \) | \( \csc(\theta) \) |
| \( -0.1 \) | \( -10.01668613 \) |
| \( -0.01 \) | \( -100.0016667 \) |
| \( -0.001 \) | \( -1000.000167 \) |
| \( -0.000001 \) | \( -1000000 \) |
| \( \theta \) | \( \csc(\theta) \) |
| \( 0.1 \) | \( 10.01668613 \) |
| \( 0.01 \) | \( 100.0016667 \) |
| \( 0.001 \) | \( 1000.000167 \) |
| \( 0.000001 \) | \( 1000000 \) |
1) csc x has a period equal to \( 2\pi \).
2) \( \csc(x) \) has vertical asymptotes at all values of \( x = n\pi \) , \( n \) being any integer.
3) The domain of \( \csc(x) \) is the set of all real numbers except \( x = n\pi \) , \( n \) being any integer.
4) The range of \( \csc(x) \) is given by: \( (-\infty , -1] \cup [1, +\infty) \)
5) \( \csc(x) \) is an odd function and its graph is symmetric with respect to the origin of the system of axes.
\( f(x) = a \csc( b x + c ) + d \)
1 - Use the scroll bar to set a = 1, b = 1, c = 0 and d = 0. Now change a , how does it affect the graph? Does it affect the range? If yes how?
2 - Set a = 1, c = 0, d = 0 and change b. For each value of b find the period from the graph and compare it to \( \dfrac{2\pi}{|b|} \), formula of the period of \( f(x) = a \csc( b x + c ) + d \). How does b affect the graph of f(x)? How does it affect the vertical asymptotes?
3 - Set a = 1, b = 1, d = 0 and change c starting from zero going slowly to positive large values. Take note of the shift, is it left or right, and compare it to \( - c / b\), formula of the phase shift of \( f(x) = a \csc( b x + c ) + d \).
4 - Set a = 1, b = 1, d = 0 and change c starting from zero going slowly to negative smaller values. Take note of the shift, is it left or right, and compare it to \( - c / b\).
5 - Repeat steps 4 and 5 above for b = 2, 3 and 4.
6 - Set a, b and c to non zero values and change d. What is the direction of the shift of the graph? How is the range of the function affected?
7 - Which of the parameters affect the positions of the vertical asymptotes? Explain analytically.
8 - Which of the parameters affect the domain of the function? Explain analytically.
9 - Which of the parameters affect the range of the cosecant function? Explain analytically.