Trigonometry of Right Triangles

Step1
First move points $A$ and $B$ in the diagram on the right to obtain different triangles and click on to update the length. Then read the lengths of segments $AC$ and $BC$ from the diagram.
$AC=$
$BC=$

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Step 2
Use Pythagora's theorem to calculate the length of the hypotenuse AB as follows:
$AB^2=AC^2+BC^2$
$AB^2=$+
$AB^2=$
The length of $AB$ is given by taking the square root
$AB=$
$AB=$

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Step 3
Calculate $\sin(\angle A)$, $\cos(\angle A)$, $\sin(\angle B)$ and $\cos(\angle B)$ using the definitions and compare $\sin(\angle A)$ and $\cos\angle B$ and then $\cos(\angle A)$ and $\sin(\angle B)$
Solution
$\sin(\angle A)=\frac{BC}{AB} = $         $\cos(\angle A)=\frac{AC}{AB} = $

$\sin(\angle B)=\frac{AC}{AB} = $         $\cos(\angle B)=\frac{BC}{AB} = $
Note:
1) $\sin(\angle A) = \cos(\angle B) = \cos(90^\circ - \angle A)$

2) $\cos(\angle A) = \sin(\angle B) = \sin(90^\circ - \angle A)$

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