Definitions, Properties, Equations, and Graphs
The absolute value function is explored through definitions, examples and exercises with solutions at the bottom of the page. The graphing of absolute value functions \( |f(x)| \) is discussed through interactive examples.
Consider the number line and a point at a distance \( x \) from the origin zero of the number line.
The absolute value of \( x \) written as \( |x| \) is the distance from zero to \( x \). Since \( |x| \) gives a distance, it is always positive or equal to zero. Hence:
\( |a - b| \) is the distance between points at \( a \) and \( b \) on the number line. For example: \( |5 - 15| = |-10| = 10 \).
Formal Definition:
\[ |x| = \left\{ \begin{array}{ll} x & x\geq 0 \\ -x & x\lt 0 \\ \end{array} \right. \]Which can be used to write:
\[ |x - a| = \left\{ \begin{array}{ll} x - a & x\geq a \\ -(x - a) = a - x & x\lt a \\ \end{array} \right. \]\( \sqrt{x^2} = |x| \) ; because the square root is positive or equal zero.
\( \sqrt{(x - a)^2} = |x - a| \)
For \( k \ge 0 \):
Function \( f(x) \) used is a quadratic function of the form:
\[ f(x) = ax^2 + bx + c \]The exploration is carried out by changing the parameters \( a \), \( b \) and \( c \) included in \( f(x) \) using the interactive panel below.
Exploration Guide:
Part 1: Evaluate the expressions
Part 2: Substitute and Evaluate the expressions
Part 3: Simplify the expressions
Part 4 & 5: Solve the Equations and Inequalities
Part 6: Graphs
Sketch the following pairs of functions in the same system of axes and explains the similarities and differences of the two graphs.
\( f(x) = x - 1 \quad , \quad h(x) = |f(x)| = |x - 1| \)
For \( x - 1 \ge 0 \) or \( x \ge 1 \), \( h(x) = | x - 1 | = x - 1 \) and we therefore have \( h(x) = f(x) \) which we can be clearly seen from the graphs.
For \( x - 1 \lt 0 \) or \( x \lt 1 \) , \( h(x) = |x - 1| = - (x - 1) = - f(x) \).
Therefore for \( x \lt 1 \), \( h(x) = - f(x) \) which means that the graph of \( h \) is a reflection of the graph of \( f \) on the x axis and this is can be clearly seen on the graphs.
\( f(x) = x^2 - 4 \quad , \quad h(x) = |f(x)| = |x^2 - 4| \)
For \( x^2 - 4 \le 0 \) or \( -2 \le x \le 2 \), \( h(x) = |(x^2 - 4)| = - (x^2 - 4) = - f(x) \). Therefore, on the interval \( -2 \le x \le 2 \), the graph of \( h \) is a reflection of the graph of \( f \). Outside this interval, the two graphs coincide.
\( f(x) = \sin(x) \quad , \quad h(x) = |\sin(x)| \)
Over intervals \( -2\pi \) to \( -\pi \), \( 0 \) to \( \pi \), \( 2\pi \) to \( 3\pi \), ... \( \sin(x) \ge 0 \) and \( h(x) = \sin(x) = f(x) \) therefore the graphs of \( h \) and \( f \) coincide.
For intervals \( -\pi \) to \( 0 \), \( \pi \) to \( 2\pi \) ... \( \sin(x) \lt 0 \), \( h(x) = | \sin(x) | = - \sin(x) \) and the graph of \( h \) is a reflection of the graph of \( f \) on the x axis.
Conclusion: In all three exercises above, the graph of \( h \) is on or above the x axis because \( h(x) = |f(x)| \) and the absolute value is positive or equal to 0.