 # How to Find the Domain of Square Root Functions?

A step by step tutorial, with detailed solutions, on how to find the domain of square root functions is presented. Matched problems to the exercises with solutions at the bottom of the page are also presented.

## Definition of the Domain of a Function

For a function f defined by an expression with variable x, the implied domain of f is the set of all real numbers variable x can take such that the expression defining the function is real. The domain can also be given explicitly.
For a square root function given by f(x) = √x to have real values, the radicand x must be positive or equal to zero.
also Step by Step Calculator to Find Domain of a Function

## Examples on How to Find the Domain of Square Root Functions with Solutions

### Example 1

Find the domain of function f defined by
f(x) = √(x - 1)

#### Solution to Example 1

• For f(x) to have real values, the radicand (expression under the radical) of the square root function must be positive or equal to 0. Hence
x - 1 ≥ 0
• The solution set to the above inequality is the domain of f(x) and is given by: x ≥ 1
or in interval form [1 , +∞)

#### Matched Problem 1:

Find the domain of function f defined by
f(x) = √(x + 5)

### Example 2

Find the domain of function f defined by
f(x) = √ [ (x - 2)(x + 3) ]

#### Solution to Example 2

• For f(x) to have real values, the radicand (x - 2)(x + 3) must be positive. Hence
(x - 2)(x + 3) ≥ 0
• Solve the above inequality to obtain the solution set, which is also the domain, in interval form as follows:
(-∞ , -3] ∪ [2 , + ∞)

#### Matched Problem 2:

Find the domain of function f defined by:
f(x) = √ [ - x (x + 1) ]

### Example 3

Find the domain of function f defined by:
f(x) = √ [ x2 + 2 x - 1 ]

#### Solution to Example 3

• For √ [ x2 + 2 x - 1 ] to be real, the radicand must be positive or equal to 0. Hence the inequality
x2 + 2x - 1 ≥ 0
• The solution set of the above inequality, which is also the domain, is given in interval form as follows:
(-∞ , -1-√2] ∪ [-1+ √2 , + ∞)
• The domain of the given function is given by the interval (-∞ , -1-√2] ∪ [-1+ √2 , + ∞).

#### Matched Problem 3:

Find the domain of function f defined by:
f(x) = √[ - 3 x 2 - x + 4 ]

### Example 4

Find the domain of function f defined by:
f(x) = √[ (2x - 1)/(x + 3) ]

#### Solution to Example 4

• The domain of this function is the set of all values of x such that (2x - 1)/(x + 3) ≥ 0 which is an inequality to solve. The solution set of the above inequality which is also the domain is given by
(-∞ , -3) U [ 1 / 2 , +∞)

#### Matched Problem 4:

Find the domain of function f defined by:
f(x) = √[ (- x + 1)/(3x - 2) ]

### Example 5

Find the domain of function f defined by:
f(x) = √[ |-2 x - 6| ]

#### Solution to Example 5

• The domain of this function is the set of all values of x such that |-2 x - 6| ≥ 0. We need to solve the inequality
|-2 x - 6| ≥ 0
• Because of the absolute value, the expression |-2 x - 6| is greater than or equal to 0 for all real numbers. Hence the domain of the above function is given by:

(-∞ , +∞)

#### Matched Problem 5:

Find the domain of function f defined by:
f(x) = √[ | - x + 8| ]

1. [-5 , +∞)
2. [-1 , 0]
3. [-4/3 , 1]
4. (2/3 , 1]
5. (-∞ , ∞)