๐Ÿ“š Why do we need two numbers that multiply to \( a \times c \) and add to \( b \)?

The AC Method (also called factoring by grouping) is based on a simple algebraic manipulation:

We want to factor \( ax^2 + bx + c \) into the form \( (px + q)(rx + s) \).

If we expand \( (px + q)(rx + s) \), we get:

\( (px + q)(rx + s) = pr\,x^2 + (ps + qr)x + qs \)

By comparing with \( ax^2 + bx + c \), we see:

Now, notice that \( a \times c = (pr)(qs) = (ps)(qr) \).

If we let \( m = ps \) and \( n = qr \), then:

Therefore, finding two numbers \( m \) and \( n \) that multiply to \( a \times c \) and add to \( b \) allows us to split the middle term \( bx \) into \( mx + nx \), then factor by grouping.

This method works when the quadratic is factorable over the rationals (i.e., when the discriminant \( \Delta = b^2 - 4ac \) is a perfect square).

โœง Quadratic Factoring Calculator โœง

Factor \( ax^2 + bx + c \) using the AC Method (Factoring by Grouping)

Enter coefficients for \( ax^2 + bx + c \)
\( 6x^2 + 5x - 6 \)
๐Ÿ“ Factored Form
\( 6x^2 + 5x - 6 = (2x + 3)(3x - 2) \)

๐Ÿ“– Step-by-Step Solution

STEP 1: Identify coefficients a, b, c
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STEP 2: Compute the discriminant \( \Delta = b^2 - 4ac \)
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STEP 3: Check if the discriminant is a perfect square
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STEP 4: Find two numbers that multiply to \( a \times c \) and add to \( b \)
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STEP 5: Split the middle term and factor by grouping
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STEP 6: Write the final factored form
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