Solve Linear Equations with Parentheses Using the Distributive Law

This tutorial presents detailed examples and exercises on solving linear equations with parentheses using the distributive property. Solutions include step-by-step reasoning with explanatory notes.

To remove parentheses, apply the distributive law:

\[ a(b + c) = ab + ac \]

Examples with Solutions

Example 1

Solve the equation:

\[ -2(x + 3) = x + 6 \]

Solution to Example 1

Matched Exercise 1

\[ -3(-x+3)=x-7 \]

Example 2

Solve the equation:

\[ -3(-x - 6) = 3x - 23 \]

Solution to Example 2

Matched Exercise 2

\[ 4(-x + 3) = -4x - 7 \]

Example 3

Solve the equation:

\[ -7(x - 6) - 3x - 3 = 3(x + 5) - 2x \]

Solution to Example 3

Matched Exercise 3

\[ -5(x - 4) - x + 23 = 5(x - 5) - x \]

Example 4

Solve the equation:

\[ -\,\frac{2(x - 6)}{7} - \frac{x - 3}{2} = -x \]

Solution to Example 4

Matched Exercise 4

\[ -3\,\frac{(x + 4)}{4} - x - 2 = \frac{x - 4}{3} - x \]

More References

Learn more about how to solve equations, systems of equations, and inequalities.