Formulas & steps
For a sphere with radius \( R \), the fundamental relations are:
\[ \text{Volume: } V = \frac{4}{3}\pi R^3 \qquad \text{Surface Area: } A = 4\pi R^2 \]
Depending on the selected mode, the missing values are derived:
- Mode 1 (R → V, A): Direct substitution into formulas above.
- Mode 2 (V → R, A): Solve for \( R = \left(\dfrac{3V}{4\pi}\right)^{1/3} \), then \( A = 4\pi R^2 \).
- Mode 3 (A → R, V): Solve for \( R = \sqrt{\dfrac{A}{4\pi}} \), then \( V = \dfrac{4}{3}\pi R^3 \).
Note: All values are positive. You can adjust decimal places from 0 to 10.
