Questions on solving equations and inequalities with absolute value are presented along with detailed solutions. You may want to work through the tutorials on solving equations with absolute value before solving the questions below.

The most important about the absolute value of an algebraic expression, is that we can simplify them if we know the sign of the expression inside the absolute value symbol according to the following definition.

| x | = x if x ? 0

and

| x | = - x if x < 0

Some specific equations and inequalities with absolute value may be written without the absolute value symbol as follows:

1) |x| = k , where k is a positive real number, is equivalent to x = k or x = - k

2) |x| < k , where k is a positive real number, is equivalent to - k < x < k

3) |x| > k , where k is a positive real number, is equivalent to k < 0 or x < - k

Rewrite the equation with the absolute value expression on one side

2| - 2 x - 2| = 16 , add 3 to both sides

| - 2 x - 2| = 8 , divide both sides by 2

The above equation is equivalent to stating that the expression - 2 x - 2 is equal to 8 or - 8.

a) -2 x - 2 = 8

x = - 5

b) - 2 x - 2 = - 8

x = 3

As an exercise, check by substitution that x = - 5 and x = 3 are solutions to the given equation.

Solution set: {-5,3}

The signs of x - 1 and 2 x + 1 change with x and one way to solve this equation is to consider two cases

a) assume x - 1 ? 0 and rewrite the equation as

x - 1 = 2x + 1

solve for x

x = -2

b) assume x - 1 ? 0 and rewrite the equation as

-(x - 1) = 2x + 1

- x + 1 = 2x + 1

solve for x

x = 0

Substitute x by - 2 in both sides of the given equation.

Left side: |(-2) - 1| = |-2 + 1| = 1

Right side: 2(-2) + 1 = - 3

The two sides are not equal and therefore x = -2 is not a solution to the given equation.

Substitute x by 0 in both sides of the given equation.

Left side: |(0) - 1| = 1

Right side: 2(0) + 1 = 1

The two sides are equal and therefore x = 0 is a solution to the given equation.

Solution set: {0}

x

a) assume 2 x - 1 ? 0 and rewrite the equation as

2x - 1 = x

which may be written as

x

solve for x

x = 1

b) assume 2 x - 1 ? 0 and rewrite the equation as

- (2x - 1) = x

which may be written as

x

solve for x

x = - 1 - √ 2 , - 1 + √ 2

Check all solutions found above (detailed calculations will be left out for you as an exercise)

All solutions found above (1 , - 1 - √ 2 and - 1 + √ 2) are solutions to the original equation given above.

Rewrite the given equation with the term containing the absolute value on one side.

-2|x + 1| = 6

|x + 1| = - 3

The absolute value of an algebraic expression cannot be negative and therefore the given equation has no solutions.

Note that x

x

|x - 1| = |x - 1|

Rewrite the above as

|x - 1|

Factor

|x - 1|(|x - 1| - 1) = 0

which gives

|x - 1| = 0 and solution x = 1

or

|x - 1| - 1 = 0 |x - 1| = 1 Solve the above to obtain two solutions x = 1 and x = 2.

We did not make any assumptions as in the above questions and we therefore do not need to check our solutions (except perhaps for mistakes made).

Solution set: {0,1,2}

The above inequality is solved by writing a double inequality equivalent to the given inequality but without absolute value

- 3 < x + 2 < 3

Solve the double inequality to obtain

- 5 < x < 1

The above solution set is written in interval form as follows

(-5 , 1)

Divide both sides of the given inequality by - 3 and change the symbol of the inequality to obtain

|-2x + 4| ? - 4 / 3

The absolute value of an expression is always positive or equal to zero. Hence any value of x in the above inequality will satisfy it and therefore the solution set of the given inequality is the set of all the real numbers given by

\( (-\infty , \infty) \)

Solving the above inequality is equivalent to solving

-2 x - 4 > 9 or -2 x - 4 < - 9

Which gives

\( x \lt -13 / 2\) or \( x \gt 5 / 2 \)

The above solution set is written in interval form as follows

\( (-\infty , -13 / 2) \cup (5 / 2 , + \infty) \)

Note that the algebraic expression |x

|x

Hence the inequality may be written as

|x + 1| - |x + 1|

|x + 1| is positive or equal to zero, hence the left side of above inequality may be factored as

|x + 1|(1 - |x + 1|) ? 0

We now use a table to study the sign of the two factors on the left side of the above inequality to determine the solution set.

|x + 1| is positive for all values of x except at x = - 1 where it is equal to zero.

The zeros of (1 - |x + 1|) are - 2 and 0.

The table of signs is shown below.

\( (-\infty , - 2] \cup {\{-1\}} \cup [0 , + \infty) \)

Check the above answer to the inequality graphically using the graphs of the two sides (|x + 1| in blue and |x

One way to take out the absolute value is to study the sign of the expression inside the absolute value symbol. There are two cases

For \( x^2 - 4 \ge 0 \), or \( x\) in the interval \( (-\infty , -2] \cup [2 , +\infty)\), we can write

\( |x^2 - 4| = x^2 - 4 \)

Substitute the expression with the absolute value in the given inequality and solve

\( x + 2 \lt x^2 - 4\)

\( x^2 - x - 6 \gt 0\)

The solution set to above inequality is given by the interval

\( (-\infty , -2) \cup (3 , +\infty)\)

We need to select only the solutions within the interval \( (-\infty , -2] \cup [2 , +\infty)\). The intersection of intervals \((-\infty , -2] \cup [2 , +\infty)\) and \((-\infty , -2) \cup (3 , +\infty)\) gives the solution set

\((-\infty , -2) \cup (3 , +\infty)\)

For \(x^2 - 4 \lt 0\), or \(x\) in the interval \((-2 , 2)\), we can write

\( |x^2 - 4| = -(x^2 - 4) \)

Substitute the expression with the absolute value in the given inequality and solve

\(x + 2 \lt -(x^2 - 4)\)

which may be rewritten as

\(x^2 + x - 2 \lt 0\)

Solution set to the above inequality is given by the interval: (-2 , 1)

We need to select only the solutions within the interval \((-2 , 2)\). The solution set to above inequality is given by the intersection of the intervals \((-2 , 1)\) and \((-2 , 2)\) which gives

(-2 , 1)

Conclusion: The solution set to the given inequality is

\((-\infty, -2) \cup (-2 , 1) \cup (3 , +\infty)\)

Check the above answer to the inequality graphically using the graphs of the two sides of the given inequality shown below.

Solve Equations with Absolute Value.

Absolute Value Functions.

Definition of the Absolute Value Function.

Maths Problems, Questions and Online Self Tests.