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# Find The Area of an Ellipse Using Calculus

Find the area of an ellipse using integrals and calculus.

 Problem : Find the area of an ellipse with half axes a and b. Solution to the problem: The equation of the ellipse shown above may be written in the form x 2 / a 2 + y 2 / b 2 = 1 Since the ellipse is symmetric with respect to the x and y axes, we can find the area of one quarter and multiply by 4 in order to obtain the total area. Solve the above equation for y y = ~+mn~ b √ [ 1 - x 2 / a 2 ] The upper part of the ellipse (y positive) is given by y = b √ [ 1 - x 2 / a 2 ] We now use integrals to find the area of the upper right quarter of the ellipse as follows (1 / 4) Area of ellipse = 0a b √ [ 1 - x 2 / a 2 ] dx We now make the substitution sin t = x / a so that dx = a cos t dt and the area is given by (1 / 4) Area of ellipse = 0π/2 a b ( √ [ 1 - sin2 t ] ) cos t dt √ [ 1 - sin2 t ] = cos t since t varies from 0 to π/2, hence (1 / 4) Area of ellipse = 0π/2 a b cos2 t dt Use the trigonometric identity cos2 t = ( cos 2t + 1 ) / 2 to linearise the integrand; (1 / 4) Area of ellipse = 0π/2 a b ( cos 2t + 1 ) / 2 dt Evaluate the integral (1 / 4) Area of ellipse = (1/2) b a [ (1/2) sin 2t + t ]0π/2 = (1/4) π a b Obtain the total area of the ellipse by multiplying by 4 Area of ellipse = 4 * (1/4) π a b = π a b More references on integrals and their applications in calculus.