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Integrals Involving sin x , cos x and Exponential Functions
Tutorial to find integrals involving the product of sin x or cos x with exponential functions. Exercises with answers are at the bottom of the page.
All the integrals included in the examples belo are evaluated using Integration by Parts given by:
The integration by parts helps in evaluating integral of product of functions of the form U dV/dx .
Examples
In what follows, C is the constant of integration.
Example 1
Evaluate the integral
∫sin(x)exdx
Solution to Example 1:
Let u=sin(x) and dvdx=ex which gives u′=cos(x) and v=∫exdx=ex.
Use the integration by parts
as follows
We apply the integration by parts to the term ∫cos(x)exdx in the expression above, hence
Simplify the above and rewrite as
Note that the term on the right is the integral we are trying to evaluate, hence the above may be written as follows
Hence the integral is given by
Example 2
Evaluate the integral
∫cos(2x)exdx
Solution to Example 2:
Substitution: Let u=cos(2x) and dvdx=ex which gives u′=−2sin(2x) and v=∫exdx=ex :
Apply the integration by parts:
∫cos(2x)exdx=cos(2x)ex−∫−2sin(2x)exdx
= cos(2x)ex+2∫sin(2x)exdx
Apply integration by parts to the term on the right
= cos(2x)ex+2(sin(2x)ex−2∫cos(2x)exdx)
= cos(2x)ex+2sin(2x)ex−4∫cos(2x)exdx
Note that the term on the right is related to the integral we are trying to evaluate, we can write that
5∫cos(2x)exdx=cos(2x)ex+2sin(2x)ex
The given integral is evaluated as
∫cos(2x)exdx=15ex(cos(2x)+2sin(2x))+C
Example 3
Evaluate the integral
∫sin(3x+2)e3xdx
Solution to Example 3:
Substitution: Let u=sin(3x+2) and dvdx=e3x which gives u′=3cos(3x+2) and v=∫e3xdx=13e3x.
Apply the integration by parts
∫sin(3x+2)e3xdx=sin(3x+2)13e3x−∫cos(3x+2)13e3xdx
Apply the integration by parts one more time to the term ∫cos(3x+2)e3xdx
∫sin(3x+2)e3xdx=13sin(3x+2)e3x−(cos(3x+2)13e3x+∫sin(3x+2)e3xdx)
Note that the term on the right is the integral to be evaluated, hence the above may be written as
2∫sin(3x+2)e3xdx=13sin(3x+2)e3x=13sin(3x+2)e3x−(cos(3x+2)13e3x
Divide all terms by 2 and simplify
∫sin(3x+2)e3xdx=16e3x(sin(3x+2)−cos(3x+2))+C
Example 4
Evaluate the integral
∫cos(4x)e2x+5dx
Solution to Example 4:
Substitution: Let u=cos(4x) and dvdx=e2x+5 and apply the integration by parts twice
∫cos(4x)e2x+5dx=cos(4x)12e2x+5+2∫sin(4x)e2x+5dx
= cos(4x)12e2x+5+2{sin(4x)12e2x+5−2∫cos(4x)e2x+5dx}
The term on the right is the integral to be evaluated, hence
∫cos(4x)e2x+5dx=110e2x+5(cos(4x)+2sin(4x))+C
Exercises
Evaluate the following integrals.
1. ∫cos(x)exdx
2. ∫sin(2x)e3xdx
3. ∫cos(−3x+5)e5xdx
4. ∫sin(−4x+3)e−2x+1dx
Answers to Above Exercises
1. 12ex(cos(x)+sin(x))+C
2. 113e3x(3sin(2x)−2cos(2x))+C
3. 134e5x(5cos(−3x+5)−3sin(−3x+5))+C
4. 110e−2x+1(2cos(−4x+3)−sin(−4x+3))+C
More References and links