Rules of Integrals with Examples

A tutorial, with examples and detailed solutions, in using the rules of indefinite integrals in calculus is presented. A set of questions with solutions is also included.

In what follows, C is a constant of integration and can take any value.

1 - Integral of a power function: f(x) = x ⁿ

Example: Evaluate the integral

∫x ⁵ dx
Solution:
∫x ⁵ dx = x^{5 + 1} / ( 5 + 1) + c = x ⁶ / 6 + c

2 - Integral of a function f multiplied by a constant k: k f(x)

Example: Evaluate the integral

∫5 sinx dx
Solution:
According to the above rule
∫ 5 sin (x) dx = 5 ∫ sin(x) dx
∫ sin(x) dx   is given by 2.1 in table of integral formulas , hence
∫ 5 sin(x) dx = - 5 cos x + C

3 - Integral of Sum of Functions.

Example: Evaluate the integral

∫[x + e ^x] dx
Solution:
According to the above property
∫ [x + e ^x ] dx = ∫ x dx + ∫ e ^x dx
ò x dx is given by 1.3 and ∫ e ^x dx by 4.1 in table of integral formulas , hence
∫ [x + e ^x ] dx = x ² / 2 + e ^x + c

4 - Integral of Difference of Functions.

Example: Evaluate the integral

∫[2 - 1/x] dx
Solution:
According to the above property
∫ [2 - 1/x] dx = ∫ 2 dx - ∫ (1/x) dx
∫ 2 dx is given by 1.2 and ∫ (1/x) dx by 1.4 in table of integral formulas , hence
∫ [2 - 1/x] dx = 2x - ln |x| + c

5 - Integration by Substitution.

Example: Evaluate the integral

∫(x ² - 1) ²⁰ 2x dx
Solution:
Let u = x ² - 1, du/dx = 2x and the given integral can be written as
∫ (x ² - 1) ²⁰ 2x dx
= ∫ u ²⁰ (du/dx) dx
= ∫ u ²⁰ du         according to above property
= u ²¹ / 21 + c = (x ² - 1) ²¹ / 21 + c

6 - Integration by Parts.

Example: Evaluate the integral

∫x cos x dx
Solution:
Let f(x) = x and g ' (x) = cos x which gives
f ' (x) = 1 and g(x) = sin x
From integration by parts formula above,
∫ x cos x dx = x sin x - ∫ 1 sin x dx
= x sin x + cos x + c

More Questions with Solutions

Use the table of integral formulas and the rules above to evaluate the following integrals. [Note that you may need to use more than one of the above rules for one integral].
1. ∫(1 / 2) ln (x) dx
2. ∫[sin (x) + x ⁵] dx
3. ∫[sinh (x) - 3] dx
4. ∫ - x sin (x) dx

5. ∫ sin ¹⁰(x) cos(x) dx

Solutions to the Above Questions

1.
This is the integral of ln (x) multiplied by 1 / 2 and we therefore use rule 2 above to obtain:
∫ (1 / 2) ln (x) dx = (1 / 2) ∫ ln (x) dx
We now use formula 4.3 in the table of integral formulas to evaluate ∫ ln (x) dx. Hence
∫ (1 / 2) ln (x) dx = (1 / 2) ( (x ln (x)) - x ) + c

2.
Use rule 3 ( integral of a sum ) to obtain
∫ [sin (x) + x ⁵ ] dx = ∫ sin (x) dx + ∫ x ⁵ dx
We use formula 2.1 in the table of integral formulas to evaluate ∫ sin (x) dx and rule 1 above to evaluate ∫ x ⁵ dx. Hence
∫ [sin (x) + x ⁵ ] dx = - cos (x) + x ⁶ / 6
3.
Use rule 4 (integral of a difference) to obtain
∫ (sinh (x) - 3) dx = ∫ sinh (x) dx - ∫ 3 dx
We use formula 7.1 in the table of integral formulas to evaluate ∫ sinh (x) dx and integral of the constant 3 to obtain
∫ (sinh (x) - 3) dx = cosh (x) - 3 x + c
4.
The integrand is the product of two function x and sin (x) and we try to use integration by parts in rule 6 as follows:
Let f(x) = x , g'(x) = sin(x) and therefore g(x) = - cos(x)
Hence
∫ - x sin (x) dx = - ∫ f(x) g'(x) dx = - ( f(x) g(x) - ∫ f'(x) g(x) dx)
Substitute f(x), f'(x), g(x) and g'(x) by x , 1, sin(x) and - cos(x) respectively to write the integral as
= - x (- cos(x)) + ∫ 1 (- cos(x)) dx
Use formula 2.2 in in the table of integral formulas to evaluate ∫ cos(x) dx and simplify to obtain
= x cos (x) - sin(x) + c

5.
Let u = sin(x) and therefore du/dx = cos(x). Hence the given integral can be written as
∫ sin ¹⁰ (x) cos dx = ∫ ( u ¹⁰ du/dx ) dx
Use rule 5 to write
= ∫ u ¹⁰ du
which gives
= u ¹¹ / 11 + c
Substitute u by sin(x) to obtain
= (1 / 11) (sin ¹¹ (x) ) + c

More References and Links

Table of Integral Formulas
integrals and their applications in calculus.
evaluate integrals .
Integration by Substitution .