Integrals Involving \( \sin(x) \) with Odd Power

Tutorial to find integrals involving odd powers of \( \sin(x) \). Exercises with answers are at the bottom of the page.

Examples with Detailed Solutions

In what follows, C is the constant of integration.

Example 1

Evaluate the integral \[ \int \sin^3(x) \, dx \] Solution to Example 1:
The main idea is to rewrite the power of \( \sin(x) \) as the product of a term with power 1 and a term with an even power.
Example: \( \sin^3(x) = \sin^2(x) \sin(x) \). Hence the given integral may be written as follows:
\( \displaystyle \int \sin^3(x) \, dx = \int \sin^2(x) \sin(x) \, dx \)
Use the identity : \( \sin^2 x = 1 - \cos^2(x) \) to write
\( \displaystyle \int \sin^3(x) \, dx = \int (1 - \cos^2(x)) \sin(x) \, dx \)
We now let \( u = \cos(x) \), hence \( \dfrac{du}{dx} = -\sin(x) \) or \( -du = \sin(x) \, dx \) and substitute in the given integral to obtain
\( \displaystyle \int \sin^3(x) \, dx = - \int (1 - u^2) \, du \)
\( \displaystyle \int \sin^3(x) \, dx = \dfrac{1}{3} u^3 - u + C \)
Substitute \( u \) by \( \cos(x) \) to obtain \[ \int \sin^3(x) \, dx = \dfrac{1}{3}\cos^3(x) - \cos(x) + C \]

Example 2

Evaluate the integral \[ \int \sin^5(x) \, dx \] Solution to Example 2:
Rewrite \( \sin^5(x) \) as follows \( \sin^5(x) = \sin^4(x) \sin(x) \). Hence the given integral may be written as follows:
\( \displaystyle \int \sin^5(x) \, dx = \int \sin^4(x) \sin(x) \, dx \)
We now use the identity \( \sin^2(x) = 1 - \cos^2(x) \) to rewrite \( \sin^4(x) \) in terms of power of \( \cos(x) \) and rewrite the given integral as follows:
\( \displaystyle \int \sin^5(x) \, dx = \int (1 - \cos^2(x))^2 \sin(x) \, dx \)
We now let \( u = \cos(x) \), hence \( \dfrac{du}{dx} = -\sin(x) \) or \( du = -\sin(x) \, dx \) and substitute in the given integral to obtain
\( \displaystyle \int \sin^5(x) \, dx = - \int (1 - u^2)^2 \, du \)
Expand and calculate the integral on the right
\( \displaystyle \int \sin^5(x) \, dx = - \int (u^4 - 2u^2 + 1) \, du \)
\( = -(\dfrac{1}{5}u^5 - \dfrac{2}{3}u^3 + u) + C \)
and finally \[ \int \sin^5(x) \, dx = -(\dfrac{1}{5}\cos^5(x) - \dfrac{2}{3}\cos^3(x) + \cos(x)) + C \]

Exercises

Evaluate the following integrals.
1. \( \displaystyle \int \sin^7(x) \, dx \)
2. \( \displaystyle \int \sin^9(x) \, dx \)

Answers to Above Exercises

1. \( \dfrac{1}{7}\cos^7(x) - \dfrac{3}{5}\cos^5(x) + \cos^3(x) - \cos(x) + C \)
2. \( -\dfrac{1}{9}\cos^9(x) + \dfrac{4}{7}\cos^7(x) - \dfrac{6}{5}\cos^5(x) + \dfrac{4}{3}\cos^3(x) - \cos(x) + C \)

More References and links

integrals and their applications in calculus.