Graphical Approximation of Derivatives - Part(3)
Approximate graphically the first
derivative
of a function \( f \) from its graph. Each question is followed by a detailed solution explaining the reasoning.
Question 1
Below is shown the graph of a function \( f \).
a) Assuming that the only extrema of \( f \) are the ones shown on the graph, for which values of \( x \) is
\[
f'(x) = 0 \, ?
\]
b) Assuming that the graph of \( f \) rises indefinitely to the left and to the right, determine the intervals where
\[
f'(x) < 0 \quad \text{and} \quad f'(x) > 0 .
\]
Solution to Question 1
-
a) The graph of \( f \) has two local minima at
\[
x = -2 \quad \text{and} \quad x = 4
\]
and one local maximum at
\[
x = 1 .
\]
Therefore,
\[
f'(x) = 0 \quad \text{for} \quad x = -2,\; 1,\; 4 .
\]
-
b) The function \( f \) is decreasing on the intervals
\[
(-\infty, -2) \quad \text{and} \quad (1, 4),
\]
so
\[
f'(x) < 0 \quad \text{on these intervals.}
\]
-
The function \( f \) is increasing on
\[
(-2, 1) \quad \text{and} \quad (4, +\infty),
\]
hence
\[
f'(x) > 0 \quad \text{on these intervals.}
\]
Question 2
The graph of a function \( f \) is shown below. Assuming that \( f \) is an odd function and has horizontal asymptotes, approximate graphically the graph of its first derivative \( f'(x) \).
Solution to Question 2
-
The function \( f \) is increasing for all \( x \), so
\[
f'(x) > 0 \quad \text{for all } x,
\]
and the graph of \( f'(x) \) lies above the \( x \)-axis.
-
The value \( f'(a) \) equals the slope of the tangent line to the graph of \( f \) at the point \( (a, f(a)) \).
From the graph, the slope appears to be largest near the origin \( (0,0) \).
-
Using points \( A(x_A, y_A) \) and \( C(x_C, y_C) \) near the origin,
\[
m_0 \approx \frac{y_C - y_A}{x_C - x_A}
= \frac{0.5 - (-0.5)}{0.5 - (-0.5)} = 1 .
\]
-
Using points \( C \) and \( E \), the slope near point \( D \) is approximated by
\[
m_1 \approx \frac{1 - 0.5}{1.5 - 0.5} = 0.5 .
\]
-
Since \( f \) has horizontal asymptotes,
\[
\lim_{x \to \pm\infty} f'(x) = 0 .
\]
-
Combining this information, a reasonable approximation of \( f'(x) \) is shown below in blue.
Question 3
Approximate the graph of the first derivative \( f'(x) \) of the function \( f \) shown below.
Assume that the graph of \( f \) is symmetric with respect to the vertical line
\[
x = -0.5
\]
and that \( y = 0 \) is a horizontal asymptote.
Solution to Question 3
-
The derivative satisfies
\[
f'(x) = 0 \quad \text{at} \quad x = -2,\; -0.5,\; 1,
\]
which correspond to the extrema of \( f \).
-
Using points \( D, E, F \), the slope at point \( E \) is approximated by
\[
m_0 \approx \frac{0.8 - 0.4}{-2.4 - (-2.9)} = 0.8 .
\]
-
Using the next group of three points to the right gives a slope close to
\[
-0.8 .
\]
These values allow us to plot approximate points of \( f'(x) \).
-
The derivative is positive where \( f \) is increasing:
\[
(-\infty, -2) \quad \text{and} \quad (-0.5, 1).
\]
-
The derivative is negative where \( f \) is decreasing:
\[
(-2, -0.5) \quad \text{and} \quad (1, +\infty).
\]
-
A possible approximation of \( f'(x) \) is shown below in blue:
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