Complex Numbers - Basic Operations

Tutorial on basic operations such as addition, subtraction, multiplication, division, and equality of complex numbers with online calculators and examples are presented. Practice exercises with detailed step-by-step solutions hidden in collapsible dropdowns are also included.

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Definition of Complex Numbers

A complex number \( z \) is a number of the form:

$$ z = a + bi $$

where \( a \) and \( b \) are real numbers and \( i \) is the imaginary unit defined by:

$$ i = \sqrt{-1} $$

\( a \) is called the real part of \( z \) and \( b \) is the imaginary part of \( z \).

Note that the set \( \mathbb{R} \) of all real numbers is a subset of the complex numbers \( \mathbb{C} \) since any real number may be considered as a complex number having an imaginary part equal to zero.

Complex Conjugate

The conjugate of a complex number \( a + bi \) is a complex number equal to:

$$ a - bi $$

Example: Find the conjugate of the following complex numbers:

View Solution
  • a) \( 2 + i \)
  • b) \( -3 - 4i \)
  • c) \( 5 \)
  • d) \( 5i \)

Addition of Complex Numbers

Addition of two complex numbers \( a + bi \) and \( c + di \) is defined as follows:

$$ (a + bi) + (c + di) = (a + c) + (b + d)i $$

This is similar to grouping like terms: real parts are added to real parts and imaginary parts are added to imaginary parts.

Example: Express the following in the form of a complex number \( a + bi \):

View Solution
  • \( (2 + 3i) + (-4 + 5i) = (2 - 4) + (3 + 5)i = -2 + 8i \) (or by grouping: \( 2 + 3i - 4 + 5i = -2 + 8i \))
  • \( (3i) + (-5 + 6i) = (0 - 5) + (3 + 6)i = -5 + 9i \)
  • \( (2) + (-2 + 9i) = (2 - 2) + 9i = 9i \)

An online calculator to add complex numbers for practice is available.

Subtraction of Complex Numbers

The subtraction of two complex numbers \( a + bi \) and \( c + di \) is defined as follows:

$$ (a + bi) - (c + di) = (a - c) + (b - d)i $$

Example: Express in the form of a complex number \( a + bi \):

View Solution
  • \( (2 - 5i) - (-4 - 5i) = (2 - (-4)) + (-5 - (-5))i = 6 \) (alternatively: \( 2 - 5i + 4 + 5i = 6 \))
  • \( (-7i) - (-5 - 6i) = (0 - (-5)) + (-7 - (-6))i = 5 - i \)
  • \( (2) - (2 + 6i) = (2 - 2) - 6i = -6i \)

Multiply Complex Numbers

The multiplication of two complex numbers \( a + bi \) and \( c + di \) is defined as follows:

$$ (a + bi)(c + di) = (ac - bd) + (ad + bc)i $$

However, you do not need to memorize the definition as multiplication can be carried out using ordinary algebraic distribution along with the property \( i^2 = -1 \).

Example: Express in the form of a complex number \( a + bi \): \( (3 + 2i)(3 - 3i) \)

View Solution

Using the distributive law:

$$ (3 + 2i)(3 - 3i) = (3 + 2i)(3) + (3 + 2i)(-3i) = 9 + 6i - 9i - 6i^2 $$

Grouping like terms and substituting \( i^2 = -1 \):

$$ = 9 - 3i - 6(-1) = 9 - 3i + 6 = 15 - 3i $$

An online calculator to multiply complex numbers for practice is available.

Divide two Complex Numbers

We use the multiplication property of a complex number and its conjugate to divide two complex numbers.

Example: Express \( \dfrac{8 + 4i}{1 - i} \) in the form of a complex number \( a + bi \).

View Solution

Multiply the numerator and denominator by the complex conjugate of the denominator (\( 1 + i \)):

$$ \dfrac{(8 + 4i)(1 + i)}{(1 - i)(1 + i)} $$

Expand and group like terms, noting that \( i^2 = -1 \):

$$ = \dfrac{8 + 8i + 4i + 4i^2}{1 - i + i - i^2} = \dfrac{8 + 12i + 4(-1)}{1 - (-1)} = \dfrac{4 + 12i}{2} = 2 + 6i $$

An online calculator to divide complex numbers for practice is available.

Equality of two Complex Numbers

Two complex numbers \( a + ib \) and \( x + iy \) are equal if and only if their real parts are equal and their imaginary parts are equal:

$$ a + ib = x + iy \iff a = x \text{ and } b = y $$

Example: Find the real numbers \( x \) and \( y \) such that \( 2x + y + i(x - y) = 4 - i \).

View Solution

Equating the real and imaginary parts yields a system of equations:

  • Real parts: \( 2x + y = 4 \)
  • Imaginary parts: \( x - y = -1 \)

Solving the system gives \( x = 1 \) and \( y = 2 \).

Exercises

Problem 1

Find the complex conjugate of the following complex numbers:

  1. \( 2 + 6i \)
  2. \( -8i \)
  3. \( 12 \)

Problem 2

Write the following expressions in the form \( a + bi \):

  1. \( (2 - 8i) + (-6i) \)
  2. \( -8i + (3 - 9i) \)
  3. \( 6 - (3 - i) \)
  4. \( (2 - 3i)(7 - i) \)
  5. \( \dfrac{2 + 2i}{2 - 2i} \)

Solutions to Exercises

View Solutions

1) Complex Conjugates:

  1. \( 2 - 6i \)
  2. \( 8i \)
  3. \( 12 \)

2) Expressions in Standard Form:

  1. \( (2 - 8i) + (-6i) = 2 - 14i \)
  2. \( -8i + (3 - 9i) = 3 - 17i \)
  3. \( 6 - (3 - i) = 6 - 3 + i = 3 + i \)
  4. \( (2 - 3i)(7 - i) = 14 - 2i - 21i + 3i^2 = 14 - 23i - 3 = 11 - 23i \)
  5. \( \dfrac{2 + 2i}{2 - 2i} = \dfrac{(2 + 2i)(2 + 2i)}{(2 - 2i)(2 + 2i)} = \dfrac{4 + 8i + 4i^2}{4 - 4i^2} = \dfrac{8i}{8} = i \)

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