An online feet/inches and centimeters conversion calculator is presented along with problems involving length and volume conversions.
Common notations and abbreviations:
By international agreement:
\[ 1 \text{ inch} = 2.54 \text{ centimeters} \] \[ 1 \text{ foot} = 12 \text{ inches} = 12 \times 2.54 \text{ centimeters} = 30.48 \text{ centimeters} \] \[ 1 \text{ cm} = \left(\frac{1}{2.54}\right) \text{ inch} \] \[ 1 \text{ cm} = \left(\frac{1}{30.48}\right) \text{ feet} \]Reference: NIST Reference Guidelines
Enter the number of feet and inches (or centimeters) to perform conversions with customizable decimal places.
Convert \( 3'11'' \) to cm and round the answer to 1 decimal place.
Note that \( 3'11'' = 3 \text{ feet} + 11 \text{ inches} \).
\[ 3'11'' = 3 \times 30.48 \, \text{cm} + 11 \times 2.54 \, \text{cm} = 91.44 \, \text{cm} + 27.94 \, \text{cm} = 119.38 \, \text{cm} \]Rounding to 1 decimal place:
\[ 3'11'' = 119.4 \, \text{cm} \]Convert \( 78.6 \, \text{cm} \) to feet and inches and round to the nearest inch.
Separating the whole feet and the decimal part:
\[ 2.57874015748 \, \text{feet} = 2 \, \text{feet} + 0.57874015748 \, \text{feet} \]Convert the decimal part to inches (since \( 1 \text{ foot} = 12 \text{ inches} \)):
\[ 0.57874015748 \times 12 \, \text{in} \approx 6.94488188976 \, \text{in} \]Rounding to the nearest inch gives \( 7 \, \text{in} \).
Conclusion: \( 78.6 \, \text{cm} = 2 \text{ ft } 7 \text{ in} \).
A fence of length \( 70 \text{ ft } 8 \text{ in} \) is to be constructed using pallets of length \( 3 \text{ ft } 6 \text{ in} \). How many pallets are needed?
First, convert the length of the fence to cm:
\[ 70 \text{ ft } 8 \text{ in} = 70 \times 30.48 \, \text{cm} + 8 \times 2.54 \, \text{cm} = 2133.6 \, \text{cm} + 20.32 \, \text{cm} = 2153.92 \, \text{cm} \]Convert the length of one pallet to cm:
\[ 3 \text{ ft } 6 \text{ in} = 3 \times 30.48 \, \text{cm} + 6 \times 2.54 \, \text{cm} = 91.44 \, \text{cm} + 15.24 \, \text{cm} = 106.68 \, \text{cm} \]The number \( N \) of pallets needed is:
\[ N = \dfrac{\text{Length of fence}}{\text{Length of one pallet}} = \dfrac{2153.92 \, \text{cm}}{106.68 \, \text{cm}} \approx 20.190476 \]Since the number of pallets must be a whole number rounded to the next higher integer:
\[ N = 21 \text{ pallets} \]What is the area of a rectangular floor of dimensions \( 540 \, \text{cm} \) by \( 340 \, \text{cm} \) in square inches? Round the answer to the nearest tenth of a square inch.
Convert the dimensions of the floor to inches using \( 1 \, \text{cm} \approx 0.3937007874 \, \text{in} \):
\[ L = 540 \, \text{cm} = 540 \times 0.3937007874 \, \text{in} \approx 212.598425 \, \text{in} \] \[ W = 340 \, \text{cm} = 340 \times 0.3937007874 \, \text{in} \approx 133.858268 \, \text{in} \]The area \( A \) of the rectangular floor in square inches is given by \( A = L \times W \):
\[ A = 212.598425 \times 133.858268 \approx 28,458.089 \, \text{in}^2 \]Rounding to the nearest tenth of a square inch (one decimal place):
\[ A = 28,458.1 \, \text{in}^2 \]Convert the volume \( V = 123.5 \, \text{cm}^3 \) into \( \text{in}^3 \) and round to the nearest hundredth of a \( \text{in}^3 \).
By definition, \( 1 \, \text{cm}^3 = 1 \, \text{cm} \times 1 \, \text{cm} \times 1 \, \text{cm} \).
Using the conversion factor \( 1 \, \text{cm} = 0.3937007874 \, \text{inches} \):
\[ 1 \, \text{cm}^3 = (0.3937007874 \, \text{in})^3 \approx 0.061023744 \, \text{in}^3 \]Therefore:
\[ V = 123.5 \times 0.061023744 \, \text{in}^3 \approx 7.53643 \, \text{in}^3 \]Rounding to the nearest hundredth of a cubic inch (two decimal places):
\[ V = 7.54 \, \text{in}^3 \]