An easy-to-use online feet and inches calculator is presented. It can perform all 4 basic operations (\( +, -, \times, \div \)) on two quantities given in feet and inches.
Results for addition and subtraction are given in feet and inches, while multiplication results are provided in square feet (\( \text{ft}^2 \)), square inches (\( \text{in}^2 \)), square centimeters (\( \text{cm}^2 \)), square meters (\( \text{m}^2 \)), and square yards (\( \text{yd}^2 \)).
Symbols: \( 1'' = 1 \text{ in} \), \( 1' = 1 \text{ foot} \)
What is the perimeter of a rectangular garden of length \( L = 12'3'' \) and width \( W = 8'11'' \)?
The perimeter \( P \) is given by:
\[ P = 2L + 2W = 2 \times 12'3'' + 2 \times 8'11'' \]Multiply each part:
\[ P = 24'6'' + 16'22'' \]Add feet together and inches together:
\[ P = 40'28'' \]Convert \( 28'' \) into feet (since \( 12'' = 1' \)):
\[ 28'' = 2 \times 12 + 4'' = 2'4'' \]Add \( 2'4'' \) to \( 40' \):
\[ P = 42'4'' \]Find the area of a rectangular room of length \( L = 10'4'' \) and width \( W = 8'5'' \) in \( \text{in}^2 \) and \( \text{cm}^2 \).
The area \( A \) is given by \( A = L \times W \).
Convert \( L \) and \( W \) into inches ($1 \text{ foot} = 12 \text{ inches}$):
\[ L = 10 \times 12 + 4 = 124 \, \text{in} \] \[ W = 8 \times 12 + 5 = 101 \, \text{in} \]Calculate area in square inches:
\[ A = 124 \, \text{in} \times 101 \, \text{in} = 12,524 \, \text{in}^2 \]Since \( 1 \text{ in} = 2.54 \text{ cm} \), square inches can be converted to square centimeters:
\[ 1 \, \text{in}^2 = 1 \text{ in} \times 1 \text{ in} = 2.54 \, \text{cm} \times 2.54 \, \text{cm} = 6.4516 \, \text{cm}^2 \]Convert area to \( \text{cm}^2 \):
\[ A = 12,524 \times 6.4516 = 80,799.84 \, \text{cm}^2 \]Enter quantities A and B in feet (ft) and inches (in), select the operation to perform, and calculate.
Results
A piece of material of length \( 123 \text{ ft } 8 \text{ in} \) is to be cut into smaller pieces of equal length where each piece has a length of \( 3 \text{ ft } 6 \text{ in} \). What is the maximum number of pieces that can be made?
Convert the total length \( L_1 \) of the material into inches:
\[ L_1 = 123 \times 12 + 8 = 1,484 \, \text{in} \]Convert the length \( L_2 \) of each smaller piece into inches:
\[ L_2 = 3 \times 12 + 6 = 42 \, \text{in} \]Calculate the number \( N \) of pieces:
\[ N = \dfrac{L_1}{L_2} = \dfrac{1484}{42} \approx 35.3333 \]Taking the integer part, exactly 35 small pieces can be cut.
A rectangular indoor swimming pool has a length \( L = 12 \text{ ft } 6 \text{ in} \) and its width \( W \) is \( 3 \text{ ft } 10 \text{ in} \) shorter than its length. Find the width \( W \) of the swimming pool.
Set up the subtraction: \( W = 12 \text{ ft } 6 \text{ in} - 3 \text{ ft } 10 \text{ in} \).
Convert both lengths into inches:
\[ 12 \text{ ft } 6 \text{ in} = 12 \times 12 + 6 = 150 \, \text{in} \] \[ 3 \text{ ft } 10 \text{ in} = 3 \times 12 + 10 = 46 \, \text{in} \]Subtract the total inches:
\[ W = 150 - 46 = 104 \, \text{in} \]Convert back to feet and inches (dividing by 12):
\[ 104 \div 12 = 8 \text{ remainder } 8 \]Conclusion: \( W = 8'8'' \) (\( 8 \text{ ft } 8 \text{ in} \)).