An online gallons and liters conversion calculator is presented along with problems involving the conversion of gallons and liters.
Common abbreviations:
The US gallon and the Imperial gallon used (or formerly used) in the UK, Canada, and other countries have different conversion rates into liters:
\[ 1 \text{ US gallon} = 3.785412 \text{ liters} \] \[ 1 \text{ Imperial gallon} = 4.546090 \text{ liters} \] \[ 1 \text{ liter} = \left(\frac{1}{3.785412}\right) \text{ US gallon} \] \[ 1 \text{ liter} = \left(\frac{1}{4.546090}\right) \text{ Imperial gallon} \]Reference: NIST Reference Guidelines
Convert \( 11.5 \, \text{US gallons} \) to liters and round to the nearest tenth of a liter.
Rounding to the nearest tenth (one decimal place) gives:
\[ 43.5 \, \text{l} \]Convert \( 153.2 \, \text{liters} \) into US and Imperial gallons and round answers to two decimal places.
For US gallons:
\[ \dfrac{153.2}{3.785412} \approx 40.471156 \, \text{US gal} \]Rounding to two decimal places: \( 40.47 \, \text{US gal} \).
For Imperial gallons:
\[ \dfrac{153.2}{4.546090} \approx 33.699289 \, \text{Imperial gal} \]Rounding to two decimal places: \( 33.70 \, \text{Imperial gal} \).
Enter the number of gallons (selecting US or Imperial gallons) or liters (l) to perform conversions.
There are \( 158.9873 \, \text{liters} \) in one barrel of oil. How many US gallons are there in 20 barrels of oil? Round the answer to the nearest US gallon.
Twenty barrels of oil contain:
\[ 20 \times 158.9873 \, \text{l} = 3,179.746 \, \text{l} \]Convert \( 3,179.746 \, \text{l} \) into US gallons:
\[ \dfrac{3,179.746}{3.785412} \approx 839.999979 \, \text{US gal} \]Rounding to the nearest gallon gives:
\[ 840 \, \text{US gallons} \]One US gallon of gasoline costs \( \$4.20 \). What is the price of 1 liter of gasoline? Round to the nearest cent.
The price per gallon is \( \$4.20 / \text{US gal} \). Substituting \( 1 \, \text{US gal} = 3.785412 \, \text{liters} \):
\[ \dfrac{\$4.20}{3.785412 \, \text{liters}} \approx \$1.109523 / \text{liter} \]Rounding to the nearest cent (two decimal places) gives:
\[ \$1.11 / \text{liter} \]A cylindrical water tank has a radius of \( r = 50 \, \text{cm} \) and a height of \( h = 120 \, \text{cm} \). How many Imperial gallons of water can this tank hold, given that \( 1,000 \, \text{cm}^3 = 1 \, \text{liter} \)? Round the answer to the nearest tenth of a gallon.
The volume \( V \) of the cylinder is given by \( V = \pi r^2 h \):
\[ V = \pi (50)^2 (120) = 300,000\pi \, \text{cm}^3 \]Convert volume into liters knowing that \( 1,000 \, \text{cm}^3 = 1 \, \text{liter} \):
\[ V = \dfrac{300,000\pi}{1,000} = 300\pi \, \text{liters} \approx 942.4778 \, \text{liters} \]Convert volume into Imperial gallons (using \( 1 \text{ Imperial gallon} = 4.546090 \, \text{liters} \)):
\[ \dfrac{300\pi}{4.546090} \approx \dfrac{942.4778}{4.546090} \approx 207.316 \, \text{Imperial gallons} \]Rounding to the nearest tenth:
\[ 207.3 \, \text{Imperial gallons} \]