Square Feet (\( \text{ft}^2 \)) and Square Meters (\( \text{m}^2 \)) Conversion Calculator

An online square feet (\( \text{ft}^2 \)) and square meters (\( \text{m}^2 \)) conversion calculator is presented along with conversion formulas, step-by-step examples, and practical word problems.

Abbreviations:

Conversion Formula of Square Feet and Square Meters [1]

\[ 1 \text{ square foot } (\text{ft}^2) = 0.09290304 \text{ square meter } (\text{m}^2) \] \[ 1 \text{ square meter } (\text{m}^2) = \left(\frac{1}{0.09290304}\right) \text{ ft}^2 \approx 10.7639104167 \text{ ft}^2 \]

Reference: NIST Reference Guidelines

Examples of Conversion

Example 1

Convert \( 900 \, \text{ft}^2 \) to \( \text{m}^2 \) and round the answer to 1 decimal place.

View Solution
\[ 900 \, \text{ft}^2 = 900 \times 0.09290304 \, \text{m}^2 = 83.612736 \, \text{m}^2 \]

Rounding to 1 decimal place gives:

\[ 83.6 \, \text{m}^2 \]

Example 2

Convert \( 123.5 \, \text{m}^2 \) to \( \text{ft}^2 \) and round the answer to 2 decimal places.

View Solution
\[ 123.5 \, \text{m}^2 = 123.5 \times 10.7639104167 \, \text{ft}^2 \approx 1329.34293646 \, \text{ft}^2 \]

Rounding to 2 decimal places gives:

\[ 1329.34 \, \text{ft}^2 \]

Use of ft^2 and m^2 Conversion Calculators

Enter the number of \( \text{ft}^2 \) or \( \text{m}^2 \) to be converted and calculate.

ft^2         m^2
m^2         ft^2
Decimal Places

Problems Involving ft^2 and m^2 Conversions

Solutions are suggested here, but other ways to solve these questions are also possible.

Problem 1

A rectangular garden of length \( 20.4 \, \text{ft} \) and width \( 15.2 \, \text{ft} \) is to be covered with soil. If a bag of soil covers \( 2 \, \text{m}^2 \) and costs $3, how much does it cost to cover the garden?

View Solution

Area \( A \) of the garden:

\[ A = \text{length} \times \text{width} = 20.4 \, \text{ft} \times 15.2 \, \text{ft} = 310.08 \, \text{ft}^2 \]

Convert area \( A \) into \( \text{m}^2 \):

\[ A = 310.08 \times 0.09290304 \, \text{m}^2 \approx 28.807375 \, \text{m}^2 \]

Let \( N \) be the number of bags needed:

\[ N = \dfrac{28.807375 \, \text{m}^2}{2 \, \text{m}^2} = 14.403687 \]

Since the number of bags must be a whole number, round up to:

\[ N = 15 \text{ bags} \]

The total cost \( C \) is:

\[ C = 15 \times \$3 = \$45 \]

Problem 2

A house has a sitting room of length \( 8.4 \, \text{m} \), width \( 5.4 \, \text{m} \), and height \( 3.5 \, \text{m} \). How many gallons of paint are needed to paint the 4 walls of the sitting room excluding two doors of width \( 0.9 \, \text{m} \) and height \( 3.2 \, \text{m} \) each and a window of \( 1.8 \, \text{m} \) by \( 2 \, \text{m} \), if one gallon of paint covers \( 350 \, \text{ft}^2 \)?

View Solution

The total area \( A \) of the 4 walls:

\[ A = 2 \times (8.4 \times 3.5) + 2 \times (5.4 \times 3.5) = 58.8 + 37.8 = 96.6 \, \text{m}^2 \]

The two doors and the window have a total area \( B \):

\[ B = 2 \times (0.9 \times 3.2) + (1.8 \times 2) = 5.76 + 3.6 = 9.36 \, \text{m}^2 \]

The net area \( C \) to be painted:

\[ C = A - B = 96.6 - 9.36 = 87.24 \, \text{m}^2 \]

Convert area \( C \) to \( \text{ft}^2 \):

\[ C = 87.24 \times 10.7639104167 \, \text{ft}^2 \approx 939.043545 \, \text{ft}^2 \]

The number \( N \) of gallons needed:

\[ N = \dfrac{939.043545}{350} \approx 2.682982 \]

Rounding up to the next higher whole number:

\[ N = 3 \text{ gallons} \]

Problem 3

How many 6-inch square tiles are needed to cover a rectangular floor whose dimensions are \( 4 \, \text{m} \) by \( 5 \, \text{m} \)? (Note that \( 1 \, \text{foot} = 12 \, \text{inches} \))

View Solution

The total area \( A \) of the floor:

\[ A = 4 \, \text{m} \times 5 \, \text{m} = 20 \, \text{m}^2 \]

The side length \( s \) of a 6-inch tile in feet:

\[ s = \dfrac{6 \, \text{in}}{12 \, \text{in/ft}} = 0.5 \, \text{ft} \]

The area \( B \) of one tile:

\[ B = 0.5 \, \text{ft} \times 0.5 \, \text{ft} = 0.25 \, \text{ft}^2 \]

Convert tile area to \( \text{m}^2 \):

\[ B = 0.25 \times 0.09290304 \, \text{m}^2 = 0.02322576 \, \text{m}^2 \]

The minimum number \( N \) of tiles needed:

\[ N = \dfrac{20 \, \text{m}^2}{0.02322576 \, \text{m}^2} \approx 861.112833 \]

Rounding up to the next higher whole number:

\[ N = 862 \text{ tiles} \]

Problem 4

Find the area in \( \text{m}^2 \) of a square whose side is equal to \( 4 \, \text{ft} \) and \( 3 \, \text{in} \) and round the answer to 2 decimal places. (Note that \( 1 \, \text{foot} = 12 \, \text{inches} \))

View Solution

Convert \( 4 \, \text{ft} \, 3 \, \text{in} \) into decimal form:

\[ 3 \, \text{in} = \dfrac{3}{12} \, \text{ft} = 0.25 \, \text{ft} \implies 4 \, \text{ft} \, 3 \, \text{in} = 4.25 \, \text{ft} \]

Area \( A \) of the square in square feet:

\[ A = (4.25 \, \text{ft})^2 = 18.0625 \, \text{ft}^2 \]

Convert area to square meters:

\[ A = 18.0625 \times 0.09290304 \, \text{m}^2 \approx 1.678061 \, \text{m}^2 \]

Rounding to 2 decimal places:

\[ A = 1.68 \, \text{m}^2 \]

More References and Links

  1. NIST Reference Guidelines
  2. Online Calculators
  3. Units Conversion and Calculators
  4. Geometry Calculators
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