An online calculator using yards, feet and inches is presented. It can perform all 4 basic operations (+ , - , × , ÷ ) on two quantities given in yards, feet and inches. Examples and problems that may be solved with
the help of this calculator are suggested.

The results for the addition and subtraction are given in yards, feet and inches. The result for the mutliplication is given in ft^2, in^2, cm^2, m^2 and yd^2.

1 inch = 2.54 cm

1 foot = 12 inches = 12 × 2.54 centimeters = 30.48 centimeters

1 yard = 3 feet = 36 inches = 36 × 2.54 cm = 91.44 cm

1 cm = ( 1 / 2.54 ) inch

1 cm = ( 1 / 30.48 ) feet

1 cm = (1 / 91.44 ) yards

Symbols for feet and inches

1 " = 1 in

1' = 1 foot

Example 1 - A rectangular sitting room has length L = 7 yd 2'8" and width W = 5 yd 1'5" in in^2 and cm^2

The area A is given by the formula: A = L × W

Convert L and W into inches; knowing that 1yd = 3 feet, 1 foot = 12 inches, 1 yd = 36 inches.

L = 7 yd 2'8" = 7 × 36 + 2 × 12 + 8 = 284 in

W = 5 yd 1'5" = 5 × 36 + 1 × 12 + 5 = 197 in

Calculate A

A = 284 in × 197 in = 55948 in^2

Given that 1 in = 2.54 cm, A may be converted to cm^2 as follows

1 in^2 = 1 in × 1 in = 2.54 cm & 2.54 cm = 6.4516 cm^2

Hence A in cm^2 is given by

A = 55948 in^2 = 55948 × 6.4516 cm^2 = 360954.1168 cm^2

Example 2 - A rectangular field has a length L = 20 ya 2' 4" inches and width W = 45 ya 1' 7"

The perimeter P is given by

P = 2 L + 2 W = 2 × ( 20 ya 2' 4") + 2 × ( 45 ya 1' 7")

Multiply

P = 40 ya 4' 8" + 90 ya 2' 14"

Add yards together, feet together and inches together

P = 130 yd 6' 22"

Covert 22" into feet

22" = 1' + 10"

Rewrite P as

P = 130 yd 7' 10"

Convert 7' into yards

7' = 2 yards + 1'

Rewrite P as

P = 132 ya 1' 10"

Enter A and B in yards (yd) , feet (ft) and inches (in) then select the operation to perform and calculate.

Results

Problem 1

How much longer is a pole of length L1 = 12 yd 1 ft 6 in than a pole of length L2 = 7 yd 2 ft 10 in?

Solution

The pole of length L1 is L1 - L2 longer than pole of length L2.

Convert L1 and L2 in into inches knowing that 1 yard = 36 inches and 1 foot = 12 inches

L1 = 12 yd 1 ft 6 in = 12 × 36 + 1 × 12 + 6 = 450 in

L2 = 7 yd 2 ft 10 in = 7 × 36 + 2 × 12 + 10 = 286 in

L1 - L2 = 450 in - 286 in = 164 in

Convert 164 in into yards, feet and inches

L1 - L2 = 164 in = 4 yd 1 ft 8.00 in

Problem 2

A rope of 20 yd 2 ft 7 in is to be cut into smaller pieces of equal lengths and each piece has a length of 1 yd 1 ft 1 in. What is the maximum number of pieces that can be made?

Solution

Convert the length the long rope into inches knowing that 1 yard = 36 inches and 1 foot = 12 inches

20 yd 2 ft 7 = 20 × 36 + 2 × 12 + 7 = 751 in

Convert the length of the smaller pieces

1 yd 1 ft 1 in = 1 × 36 + 1 × 12 + 1 = 49 in

The number N of smaller pieces that can be made is given by

N = 751 in / 49 in = = 15.3265306122

Hence 15 small pieces can be cut from the larger rope.

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