An online calculator using yards, feet, and inches is presented. It can perform all 4 basic operations (\( +, -, \times, \div \)) on two quantities given in yards, feet, and inches.
Results for addition and subtraction are given in yards, feet, and inches. Multiplication results are provided in square feet (\( \text{ft}^2 \)), square inches (\( \text{in}^2 \)), square centimeters (\( \text{cm}^2 \)), square meters (\( \text{m}^2 \)), and square yards (\( \text{yd}^2 \)).
Symbols: \( 1'' = 1 \text{ in} \), \( 1' = 1 \text{ foot} \)
A rectangular sitting room has length \( L = 7 \text{ yd } 2'8'' \) and width \( W = 5 \text{ yd } 1'5'' \). Find the area in \( \text{in}^2 \) and \( \text{cm}^2 \).
The area \( A \) is given by \( A = L \times W \).
Convert \( L \) and \( W \) into inches (\( 1\text{ yd} = 36\text{ in}, 1\text{ ft} = 12\text{ in} \)):
\[ L = 7 \times 36 + 2 \times 12 + 8 = 252 + 24 + 8 = 284 \, \text{in} \] \[ W = 5 \times 36 + 1 \times 12 + 5 = 180 + 12 + 5 = 197 \, \text{in} \]Calculate area in square inches:
\[ A = 284 \times 197 = 55,948 \, \text{in}^2 \]Since \( 1 \, \text{in} = 2.54 \, \text{cm} \), square inches convert to square centimeters via \( 1 \, \text{in}^2 = 6.4516 \, \text{cm}^2 \):
\[ A = 55,948 \times 6.4516 = 360,954.1168 \, \text{cm}^2 \]A rectangular field has length \( L = 20 \text{ yd } 2'4'' \) and width \( W = 45 \text{ yd } 1'7'' \). Find its perimeter \( P \).
The perimeter \( P \) is given by \( P = 2L + 2W \):
\[ P = 2 \times (20 \text{ yd } 2'4'') + 2 \times (45 \text{ yd } 1'7'') \]Multiply each part:
\[ P = 40 \text{ yd } 4'8'' + 90 \text{ yd } 2'14'' \]Add yards together, feet together, and inches together:
\[ P = 130 \text{ yd } 6'22'' \]Convert \( 22'' \) into feet (\( 22'' = 1'10'' \)):
\[ P = 130 \text{ yd } 7'10'' \]Convert \( 7' \) into yards (\( 7' = 2 \text{ yd } 1' \)):
\[ P = 132 \text{ yd } 1'10'' \]Enter quantities A and B in yards (yd), feet (ft), and inches (in), select the operation to perform, and calculate.
Results
How much longer is a pole of length \( L_1 = 12 \text{ yd } 1 \text{ ft } 6 \text{ in} \) than a pole of length \( L_2 = 7 \text{ yd } 2 \text{ ft } 10 \text{ in} \)?
Convert both lengths into inches:
\[ L_1 = 12 \times 36 + 1 \times 12 + 6 = 432 + 12 + 6 = 450 \, \text{in} \] \[ L_2 = 7 \times 36 + 2 \times 12 + 10 = 252 + 24 + 10 = 286 \, \text{in} \]Find the difference:
\[ L_1 - L_2 = 450 - 286 = 164 \, \text{in} \]Convert \( 164 \, \text{in} \) back into yards, feet, and inches:
\[ 164 \div 36 = 4 \text{ yd remainder } 20 \text{ in} \] \[ 20 \div 12 = 1 \text{ ft remainder } 8 \text{ in} \]Conclusion: \( 4 \text{ yd } 1 \text{ ft } 8 \text{ in} \).
A rope of length \( 20 \text{ yd } 2 \text{ ft } 7 \text{ in} \) is to be cut into smaller pieces of equal length where each piece has a length of \( 1 \text{ yd } 1 \text{ ft } 1 \text{ in} \). What is the maximum number of pieces that can be made?
Convert the total rope length into inches:
\[ 20 \times 36 + 2 \times 12 + 7 = 720 + 24 + 7 = 751 \, \text{in} \]Convert each smaller piece length into inches:
\[ 1 \times 36 + 1 \times 12 + 1 = 49 \, \text{in} \]Calculate the number \( N \) of smaller pieces:
\[ N = \dfrac{751}{49} \approx 15.3265 \]Taking the integer part, exactly 15 small pieces can be cut.