An online conversion calculator of yards, feet, inches and meters is presented. Examples and problems involving conversion of yards, feet, inches and meters are also included.

1 inch = 2.54 cm

1 foot = 12 inches = 12 × 2.54 centimeters = 30.48 centimeters

1 yard = 3 feet = 36 inches = 36 × 2.54 centimeters = 91.44 centimeters

1 centimeters = ( 1 / 2.54 ) inch

1 centimeters = ( 1 / 30.48 ) feet

1 centimeters = (1 / 91.44 ) yards

1 meter = 100 centimeter

1 centimeter = (1 / 100 ) meters

1 yard = 1 yd

1 inch = 1 in = 1"

1 foot = 1 ft = 1'

1 centimeter = 1 cm

1 meter = 1 m

Example 1 - Convert 12 yd 2 feet 7 in to meters and round the answer to the nearest unit.

Given that 1 yard = 91.44 cm, 1 foot = 30.48 centimeters and 1 inch = 2.54 cm,

12 yd 2 feet 7 in = 12 × 91.44 cm + 2 × 30.48 cm + 7 × 2.54 cm = 1176.02 cm

Given that 1 cm = (1 / 100 ) m

12 yd 2 feet 7 in = 1176.02 cm = 1176.02 * (1 / 100 ) m = 11.7602 m

Round to the nearest unit

12 yd 2 feet 7 in = 12 m

Example 2 - Convert 15.25 meter to yards, feet and inches

1 m = 100 cm

15.25 m = 15.25 × 100 cm = 1525 cm

Given that 1 yd = 91.44 cm, 1 cm = ( 1 / 91.44 ) yd

Hence

15.25 m = 1525 cm = 1525 × ( 1 / 91.44 ) yd = 16.6776027997 yd

16.6776027997 yd = 16 yd + 0.6776027997 yd

Given that 1 yd = 3 feet

16.6776027997 yd = 16 yd + 0.6776027997 × 3 ft = 16 yd + 2.0328083991 ft

Given that 1 ft = 12 in

16.6776027997 yd = 16 yd + 0.6776027997 × 3 ft = 16 yd + 2 ft + 0.0328083991 × 12 in = 16 yd + 2 ft + 0.3937007892 in

Round to the nearest inch

15.25 m = 16 yd 2 ft 0 in

Enter the number of yd ft in or the number of m and convert.

Problem 1

It costs $12.5 per (linear) meter to fence a rectangular field of length L = 25 yd 2 ft and width W = 20 yd 1 ft. What is the total cost of fencing the field along its perimeter?

Solution

Since the cost is per meter, convert the length and width in meters. Given that 1 foot = 30.48 centimeters, 1 yard = 91.44 cm and 1 cm = (1 / 100 ) m

L = 25 yd 2 ft = 25 × 91.44 cm + 2 × 30.48 cm = 2346.96 cm = 2346.96 × (1 / 100 ) m = 23.4696 m

W = 20 yd 1 ft = 20 × 91.44 cm + 1 × 30.48 cm = 1859.28 cm = 1859.28 × (1 / 100 ) m = 18.5928 m

The perimeter P is given by

P = 2 (L + W) = 2 ( 23.4696 m + 18.5928 m) = 84.1248 m

Total cost = 84.1248 m × $12.5/m = $1051.56

Problem 2

Convert the speed of 121.5 yd / sec into m / sec and round the answer to one decimal place.

Solution

Given that 1 yd = 91.44 cm and 1 cm = (1 / 100 ) m

1 yd = 91.44 cm = 91.44 × (1 / 100 ) m = 0.9144 m

Hence

121.5 yd / sec = 121.5 × 0.9144 m / sec = 111.0996 m / sec

Round to one decimal place

121.5 yd / sec = 111.1 m / sec

Problem 3

A cubic water tank with 6 square faces has 1.6 yd per side (of each square). How long does it take to fill the tank with water at the rate of 0.5 m^3 per hour?

Solution

Covert 1.2 yd into maters

1.6 yd = 1.6 × 91.44 × (1 / 100 ) m = 1.46304 m

The volume V of the cube in m^3 is given by

V = 1.46304 m * 1.46304 m * 1.46304 m = 3.1316166983 m^3

Time T taken to fill the cubic water tank is given by

T = 3.1316166983 m^3 / (0.5 m^3 / hrs ) = 6.2632333966 hrs

Convert time T into hrs , min and sec

T = 6.2632333966 hrs = 6 hrs 15 min 48 sec , time taken to fill the tank.