Thinking Skills - Grade 4 Math Questions With Answers

Grade 4 math questions on thinking are presented along with detailed step-by-step solutions and explanations. Challenging questions are necessary to develop critical thinking skills and problem-solving abilities.

Questions and Step-by-Step Solutions

  1. Question 1: John has more toys than Janet and more toys than Bill. Mark has more toys than John. Which statement is true?

    1. Janet has more toys than John.
    2. Bill has more toys than Mark.
    3. Janet has more toys than Mark.
    4. Mark has more toys than Bill.
    ► Solution to Question 1

    Let's analyze the relationships given:
    - John > Janet and John > Bill
    - Mark > John
    Combining these inequalities: Mark > John > Janet/Bill.
    Therefore, Mark has more toys than Bill.

    Option D is correct.

  2. Question 2: Jack, Toby, Jill, and Yung are lined up. Toby is behind Jack and in front of Yung. Jill is behind Yung. In what order are Jack, Toby, Jill, and Yung lined up?

    1. Yung, Toby, Jack, Jill (first)
    2. Jill, Jack, Toby, Yung (first)
    3. Jill, Toby, Jill, Yung (first)
    4. Jill, Yung, Toby, Jack (first)
    ► Solution to Question 2

    Let's order them from front to back:
    - Toby is behind Jack (Jack is in front of Toby: Jack -> Toby)
    - Toby is in front of Yung (Toby -> Yung)
    - Jill is behind Yung (Yung -> Jill)
    Putting this together from first to last: Jack, Toby, Yung, Jill.

    Option D is correct.

  3. Question 3: Malcom is older than Janette. Janette is older than Bob. Tony is older than Malcom. Which statement is correct?

    1. Bob is older than Malcom.
    2. Tony is older than all of them.
    3. Janette is older than Malcom.
    4. Tony is younger than Janette.
    ► Solution to Question 3

    Ordering by age from oldest to youngest:
    - Tony > Malcom
    - Malcom > Janette
    - Janette > Bob
    Combined: Tony > Malcom > Janette > Bob.
    Therefore, Tony is older than all of them.

    Option B is correct.

  4. Question 4: George, Billy, and Joe bought some toys. George spent more than Billy. Joe spent more than George. Which statement is correct?

    1. George spent less than Billy.
    2. Billy spent more than George.
    3. Joe spent more than Billy.
    4. George spent more than Joe.
    ► Solution to Question 4

    Comparing amounts spent (from most to least):
    - Joe > George
    - George > Billy
    Combined: Joe > George > Billy.
    Therefore, Joe spent more than Billy.

    Option C is correct.

  5. Question 5: Four people are standing in line. Jamila is standing 3 meters behind Lora and 2 meters in front of Carla. Paula is standing 4 meters in front of Laura. What is the distance between Carla and Paula?

    1. 9 meters
    2. 5 meters
    3. 4 meters
    4. 2 meters
    ► Solution to Question 5

    Let's map out positions along a line (let Lora be at position 0):
    - Lora = 0
    - Jamila is 3 meters behind Lora: Jamila = +3
    - Carla is 2 meters in front of Jamila: Carla = 3 + 2 = +5
    - Paula is 4 meters in front of Lora: Paula = 0 - 4 = -4
    Distance from Paula (-4) to Carla (+5) is \(5 - (-4) = 9\) meters.

    Option A is correct.

  6. Question 6: Tim, Claudia, and Michael collected 14 stamps. Michael collected 2 more stamps than Tim and Claudia collected 3 more stamps than Tim. How many stamps did each collect?

    1. T:3 , M:6 , C:5
    2. T:5 , M:3 , C:6
    3. T:6 , M:5 , C:3
    4. T:3 , M:5 , C:6
    ► Solution to Question 6

    Let Tim's stamps = \(T\).
    - Michael = \(T + 2\)
    - Claudia = \(T + 3\)
    Total = \(T + (T + 2) + (T + 3) = 14\)
    \(3T + 5 = 14 \implies 3T = 9 \implies T = 3\).
    Then Michael = \(3 + 2 = 5\), and Claudia = \(3 + 3 = 6\).

    Option D is correct.

  7. Question 7: Dalida, Jane, and Kristy went out for dinner. Dalida does not eat meat or fish, and Jane does not eat fish. After they ordered their dinners, the waiter brought a salad and a soup, a steak with french fries, and fish and french fries. Who ate what?

    1. Dalida : Salad & soup , Jane : steak & fries , Kristy : fish & fries
    2. Dalida : Salad & soup , Jane : fish & fries , Kristy : steak & fries
    3. Dalida : steak & fries , Jane : Salad & soup , Kristy : fish & fries
    4. Dalida : fish & fries , Jane : Salad & soup , Kristy : steak & fries
    ► Solution to Question 7

    - Dalida does not eat meat or fish, so she must eat the vegetarian option: Salad & soup.
    - Jane does not eat fish, so she cannot eat fish & fries. Since Dalida has the salad & soup, Jane must have the steak & fries.
    - Kristy therefore has the remaining dish: fish & fries.

    Option A is correct.

  8. Question 8: A large square is made up of small squares. How many squares are there altogether?

    squares, question 8

    1. 9
    2. 10
    3. 11
    4. 14
    ► Solution to Question 8

    Counting the squares in the grid pattern:
    - Nine 1x1 squares
    - Four 2x2 squares
    - One 3x3 square
    Total = \(9 + 4 + 1 = 14\) squares.

    Option D is correct.

  9. Question 9: A line can be drawn using two points. How many different lines can we draw using the 4 points shown below?

    points, question 9

    1. 4
    2. 6
    3. 5
    4. 7
    ► Solution to Question 9

    For the configuration shown in the diagram, the number of lines connecting pairs of points is 6 lines.

    Option B is correct.

  10. Question 10: What is the smallest odd 3-digit number?

    1. 999
    2. 100
    3. 101
    4. 10
    ► Solution to Question 10

    The smallest 3-digit number is 100. Since 100 is even, the next number is 101, which is odd.

    Option C is correct.

  11. Question 11: What is the largest even 3-digit number?

    1. 999
    2. 998
    3. 108
    4. 1000
    ► Solution to Question 11

    The largest 3-digit number is 999. Since 999 is odd, the largest even 3-digit number is 998.

    Option B is correct.

  12. Question 12: Find a number such that:
    1 - It is a 3-digit number, larger than 399 and smaller than 500.
    2 - The sum of its tens and ones digits is equal to 5.
    3 - The digit in the ones is larger than the digit in the tens.

    ► Solution to Question 12

    - Condition 1: Being between 399 and 500 means the hundreds digit must be 4 (4xx).
    - Condition 2: The sum of the tens and ones digits is 5. The possible pairs of digits summing to 5 are \(0 + 5\), \(1 + 4\), and \(2 + 3\).
    - Condition 3: The ones digit must be larger than the tens digit, which leaves the pair 2 and 3 (where 3 > 2).
    Putting it together, the hundreds digit is 4, the tens digit is 2, and the ones digit is 3.

    The number is 423.

  13. Question 13: Find a number such that:
    1 - It is a 3-digit number and all its digits are odd.
    2 - Its hundreds digit is equal to 3.
    3 - The sum of its hundred and tens digits is 10.
    4 - The sum of its tens and ones digits is 10.

    ► Solution to Question 13

    - Hundreds digit = 3.
    - Sum of hundreds and tens digits = 10, so \(3 + \text{tens} = 10 \implies \text{tens} = 7\).
    - Sum of tens and ones digits = 10, so \(7 + \text{ones} = 10 \implies \text{ones} = 3\).
    The number is 373, and all its digits (3, 7, 3) are odd.

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