Rate, Time Distance Problems With Solutions
The relationship between distance, rate (speed) and time
is used to solve uniform motion problems. Detailed solutions to the problems and explanations are provided.
Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Solution to Problem 5:
Problem 6 The two cars are traveling in directions that are at right angle. Let x and y be the distances traveled by the two cars in t hours. Hence x = 50 t and y = 60 t Since the two directions are at right angle, Pythagora's theorem can used to find distance D between the two cars as follows: D = sqrt ( x 2 + y 2 ) We now find the time at which D = 300 miles by solving sqrt ( x 2 + y 2 ) = 300 Square both sides and substitute x and y by 50 t and 60 t respectively to obtain the equation (50 t) 2 + (60 t) 2 = 300 2 Solve the above equations to obtain t = 3.84 hours (rounded to two decimal places) or 3 hours and 51 minutes (to the nearest minute) The two cars will 300 miles apart at 8 + 3 h 51' = 11:51 am.
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11 |
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