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Example 1
The imaginary number $i$ is defined such that $i^2=−1$. What does $i−i^2+i^3−i^4+i^5−i^6...−i^9$ equal?
- $-i$
- $-1$
- $1$
- $i$
- $0$
Solution
- We first rewrite the above sum as follows
$i−i^2+i^3−i^4+i^5−i^6...i^9=(i+i^3+i^5+i^7+i^9)-(i^2+i^4+i^6+i^8)$
- We use the the properties of $i$ given by $i^3=-i$, $i^5=i$, $i^7=-i$ and $i^9=i$ to simplify the sum $i+i^3+i^5+i^7+i^9$
$i+i^3+i^5+i^7+i^9 = i-i+i-i+i=i$
- We use the the properties of $i$ given by $i^2=-1$, $i^4=1$, $i^6=-1$ and $i^8=1$ to simplify the sum $i^2+i^4+i^6+i^8$
$i^2+i^4+i^6+i^8 = -1+1-1+1=0$
- Hence
$i−i^2+i^3−i^4+i^5−i^6...i^9= i+0=i$
Answer D
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