|
|
Example 1
What is the next term in the geometric sequence $1$,$-\dfrac{1}{3}$,$\dfrac{1}{9}$,$-\dfrac{1}{27}$,…?
- $-\dfrac{1}{81}$
- $\dfrac{1}{81}$
- $\dfrac{1}{54}$
- $-\dfrac{1}{54}$
- $-1$
Solution
- The sequence given is of the form: $a_1$, $a_2$, $a_3$, ... $a_n$. We first need to calculate the common ratio $r$ given by the division of any two successive terms ($r=\dfrac{a_{n+1}}{a_n}$)in the sequence
$r=\dfrac{a_{2}}{a_1}$ , where $a_2$ and $a_1$ are the second and first terms in the sequence
$r=\dfrac{-\dfrac{1}{3}}{1}=-\dfrac{1}{3}$
- We now calculate the fifth term using the definition of geometric sequence $a_n=r \cdot a_{n-1} $
- We need to calculate $a_5$
$a_5=a_4 \cdot \dfrac{-1}{3}=\dfrac{1}{81}$
Answer B
|