Grade 6 questions on algebraic expressions along with detailed
solutions and explanations
are presented. Remember algebraic expressions are some of the most important concepts in understanding algebra and therefore
need to be thoroughly understood.
expression | term in x | write as a multiplication | find coefficient |
---|---|---|---|
2x - 7 | 2x | 2×x | 2 |
x/2 - 10 | x÷2 | (1/2)×x | 1/2 |
- x + 7 | - x | (-1)×x | - 1 |
x + 7 | x | (1)×x | 1 |
- x/4 | - x÷4 | (-1/4)×x | - 1/4 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
2x + 7 | -1 | 2 × (-1)+7= | -2 + 7 = 5 |
2x + 7 | - 4 | 2 × (-4)+7= | - 8 + 7 = - 1 |
2x + 7 | 0 | 2 × (0)+7= | 0 + 7 = 7 |
2x + 7 | 5 | 2 × (5)+7= | 10 + 7 = 17 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
x ÷ 3 - 9 | 0 | (0) ÷ 3 - 9= | 0 - 9 = - 9 |
x ÷ 3 - 9 | 3 | (3) ÷ 3 - 9 = | 1 - 9 = - 8 |
x ÷ 3 - 9 | 9 | (9) ÷ 3 - 9 = | 3 - 9 = - 6 |
x ÷ 3 - 9 | - 12 | (-12) ÷ 3 - 9 = | - 4 - 9 = - 13 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
(- x + 2) ÷ 2 + 1 | 0 | (- (0) + 2) ÷ 2 + 1 = | = (0 +2) ÷ 2 + 1 = 2 ÷ 2 + 1 = 1 + 1 = 2 |
(- x + 2)÷2 + 1 | 2 | (-(2) + 2)÷2 + 1 = | (-2 + 2)÷2 + 1 = 0÷2 + 1 = 0 + 1 = 1 |
(- x + 2)÷2 + 1 | -2 | (- (- 2) + 2)÷2 + 1 = | (2 + 2 )÷2 + 1 = 4/2 + 1 = 2 + 1 = 3 |
(- x + 2)÷2 + 1 | - 12 | (- (-12) + 2)÷2 + 1 = | (12 + 2)÷2 + 1 = 14/2 + 1 = 7 + 1 = 8 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
12 x - 3 | 1/2 | 12 (1/2) - 3 = | = 12÷2 - 3 = 4 - 3 = 1 |
12 x - 3 | 1/6 | 12 (1/6) - 3 = | = 12÷6 - 3 = 2 - 3 = - 1 |
12 x - 3 | -3/4 | 12( - 3/4) - 3 = | = - 36÷4 - 3 = - 9 - 3 = - 12 |
12 x - 3 | -1/4 | 12 (-1/4) - 3 = | = -12÷2 - 3 = - 6 - 3 = - 9 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
- 0.1 x + 2.5 | 1 | - 0.1 × (1) + 2.5 = | = -0.1 + 2.5 = 2.4 |
- 0.1 x + 2.5 | - 1 | - 0.1 × ( - 1) + 2.5 = | = 0.1 + 2.5 = 2.6 |
- 0.1 x + 2.5 | 2 | - 0.1 × (2) + 2.5 = | = -0.2 + 2.5 = 2.3 |
- 0.1 x + 2.5 | - 2 | - 0.1 × (-2) + 2.5 = | = 0.2 + 2.5 = 2.7 |
expression | value of x | substitute x in expression by its value using brackets | evaluate |
---|---|---|---|
x + 10 | - 3 | (-3) + 10 = | = - 3 + 10 = 7 |
- x + 10 | - 3 | - (-3) + 10 = | = 3 + 10 = 13 |
x÷3 + 10 | - 3 | (-3)÷3 + 10 = | = - 1 + 10 = 9 |
- x÷3 + 10 | - 3 | - (-3)÷3 + 10 = | = 3÷3 + 10 = 1 + 10 = 11 |