Detailed Solutions to Questions on Finding Ratios
Detailed solutions to the questions on finding ratio are presented.
-
There are 3 triangles and 6 squares. Find the ratios:
- Triangles to squares
- Squares to total
- Triangles to total
Solution
-
Number of triangles = 3, number of squares = 6.
\[ \dfrac{\text{triangles}}{\text{squares}} = \dfrac{3}{6} \]
Simplify by dividing numerator and denominator by 3:
\[ \dfrac{1}{2} \; \] or \[ \;1:2\].
-
Total = \(3 + 6 = 9\).
\[ \dfrac{\text{squares}}{\text{total}} = \dfrac{6}{9} \]
Simplify: \[ \dfrac{2}{3} \; \] or \[ \;2:3\].
-
\[ \dfrac{\text{triangles}}{\text{total}} = \dfrac{3}{9} \]
Simplify: \[ \dfrac{1}{3} \; \] or \[ \;1:3\].
-
There are 300 boys and 500 girls in a school. Find the ratios:
- Boys to total
- Girls to total
- Boys to girls
Solution
Total = \(300 + 500 = 800\).
-
\[ \dfrac{\text{boys}}{\text{total}} = \dfrac{300}{800} \]
Divide numerator and denominator by 100: \[ \dfrac{3}{8} \; \] or \[ \;3:8\].
-
\[ \dfrac{\text{girls}}{\text{total}} = \dfrac{500}{800} \]
Divide numerator and denominator by 100: \[ \dfrac{5}{8} \; \] or \[ \;5:8\].
-
\[ \dfrac{\text{boys}}{\text{girls}} = \dfrac{300}{500} \]
Divide numerator and denominator by 100: \[ \dfrac{3}{5} \; \] or \[ \;3:5\].
-
There are 200 chairs and 150 tables. Find the ratios:
- Chairs to total
- Total to tables
Solution
Total = \(200 + 150 = 350\).
-
\[ \dfrac{\text{chairs}}{\text{total}} = \dfrac{200}{350} \]
Divide numerator and denominator by 50: \[ \dfrac{4}{7} \; \] or \[ \;4:7\].
-
\[ \dfrac{\text{total}}{\text{tables}} = \dfrac{350}{150} \]
Divide numerator and denominator by 50 \[ \dfrac{7}{3} \; \] or \[ \;7:3\].
-
There are 25 teachers, and 500 students of which 300 are girls. Find the ratios:
- Total students to teachers
- Boys to teachers
Solution
-
\[ \dfrac{\text{students}}{\text{teachers}} = \dfrac{500}{25} \]
Divide by 25: \[ \dfrac{20}{1} \; \] or \[ \;20:1\].
-
Number of boys = \(500 - 300 = 200\).
\[ \dfrac{\text{boys}}{\text{teachers}} = \dfrac{200}{25} \]
Divide by 25: \[ \dfrac{8}{1} \; \] or \[ \;8:1\].
-
City A has a population of 420,000 people and 200 general practitioners (GPs).
City B has a population of 460,000 people and 230 general practitioners.
Which city has a higher ratio of GPs to people?
Solution
-
City A:
\[ \dfrac{420{,}000}{200} = \dfrac{2100}{1} \; \] or \[ \;2100:1\].
-
City B:
\[ \dfrac{460{,}000}{230} = \dfrac{2000}{1} \; \] or \[ \;2000:1\].
Since \[2100:1 > 2000:1\],
City A has a higher ratio of GPs to people.
Links and References