This page is designed to help students, parents, and teachers master essential Grade 8 algebra concepts through practice questions and step-by-step solutions. Expand the hidden solutions beneath each question to reveal the reasoning behind every step, helping learners build a rock-solid foundation for high school mathematics.
The topics covered on this page include:
A) \(-2x + 5 + 10x - 9\)
B) \(3(x + 7) + 2(-x + 4) + 5x\)
A) \(\dfrac{2x - 6}{2}\)
B) \(\dfrac{-x - 2}{x + 2}\)
C) \(\dfrac{5x - 5}{10}\)
A) \(-x = 6\)
B) \(2x - 8 = -x + 4\)
C) \(2x + \dfrac{1}{2} = \dfrac{2}{3}\)
D) \(\dfrac{x}{3} + 2 = 5\)
E) \(\dfrac{-5}{x} = 2\)
A) \(x^2 - y^2\), for \(x = 4\) and \(y = 5\)
B) \(|4x - 2y|\), for \(x = -2\) and \(y = 3\)
C) \(3x^3 - 4y^4\), for \(x = -1\) and \(y = -2\)
A) \(x + 6 < 0\)
B) \(x + 1 > 5\)
C) \(2(x - 2) < 12\)
The definition of a reciprocal is: a number \(y\) is the reciprocal of \(x\) if \(x \cdot y = 1\).
A) \(3\dfrac{3}{4} + 6\dfrac{1}{7}\)
B) \((1\dfrac{3}{5}) \times (3\dfrac{1}{3}) - 2\dfrac{1}{2}\)
C) \((5\dfrac{2}{3}) \div (4\dfrac{1}{5})\)
D) \((3\dfrac{4}{7} - 1\dfrac{1}{2}) \div (2\dfrac{3}{8} + 2\dfrac{1}{4})\)
A number is divisible by 3 if the sum of its digits is divisible by 3.
A number is divisible by 4 if its last two digits form a number divisible by 4.
A number is divisible by 6 if it is divisible by BOTH 2 and 3.
A number is divisible by 9 if the sum of its digits is divisible by 9.