Operations with Monomials: Examples & Practice Questions

This lesson is designed for Grade 9 students to master operations involving monomials. A monomial is a single algebraic term consisting of a real number multiplied by variables raised to non-negative integer powers.

Below, you will find clear examples demonstrating how to identify coefficients, as well as how to add, subtract, multiply, and divide monomials. Once you review the examples, test your understanding with the practice questions, which include interactive step-by-step solutions.

1. Understanding the Coefficients of Monomials

Take a number, such as \(-2\), and a variable with an exponent, such as \(x^2\), and multiply them together: \(-2 \times x^2\). For simplicity, we remove the multiplication symbol and write it as a monomial: \(-2x^2\).

Examples of standard monomials include: \( x \), \( 2x \), \( 3x^2 \), \( -0.1x \), \( -\dfrac{3}{4}x^2y^2 \), \( -y \).

Definition: Coefficient

The coefficient of a monomial is the numerical part located at the front of the term.

Example 1: Identifying Coefficients


2. Add and Subtract Monomials

We can only add and subtract monomials that are like terms (meaning they have the exact same variables raised to the exact same powers).

Example 2: Addition and Subtraction

a) \( 2x + 4x \)

\[ \begin{aligned} \color{red}{2}x + \color{red}{4}x &= \color{red}{(2 + 4)}x \quad && \text{(factor out the variable } x\text{)} \\ &= 6x \quad && \text{(add the coefficients)} \end{aligned} \]

b) \( 3x^2 - x^2 \)

\[ \begin{aligned} \color{red}{3}x^2 \color{red}{- 1}x^2 &= \color{red}{(3 - 1)}x^2 \quad && \text{(factor out the variable } x^2\text{)} \\ &= 2x^2 \quad && \text{(subtract the coefficients)} \end{aligned} \]

c) \( 3x^2y - x^2y + 4yx^2 \)

\[ \begin{aligned} 3x^2y - 1x^2y + 4x^2y &= \color{red}{(3 - 1 + 4)}x^2y \quad && \text{(group the coefficients)} \\ &= 6x^2y \end{aligned} \]

3. Multiply Monomials

Multiplication Rule of Exponents

You can multiply any two monomials; they do not need to be like terms. Use the product rule for exponents:

\( x^m \cdot x^n = x^{m+n} \)

Example 3: Multiplication

a) \( (x)(6x) \)

\[ \begin{aligned} (\color{red}{1}\color{blue}{x})(\color{red}{6}\color{blue}{x}) &= \color{red}{(1 \cdot 6)}\color{blue}{(x \cdot x)} \quad && \text{(group coefficients and variables)} \\ &= 6x^{1+1} = 6x^2 \quad && \text{(apply exponent rule)} \end{aligned} \]

b) \( (5x^2y)(-y^2x) \)

\[ \begin{aligned} (5x^2y)(-1y^2x) &= (5 \cdot -1)(x^2 \cdot x)(y \cdot y^2) \\ &= -5 x^{2+1} y^{1+2} \\ &= -5x^3y^3 \end{aligned} \]

4. Divide Monomials

Division Rule of Exponents

You can divide any two monomials as long as the divisor is not zero. Use the quotient rule for exponents:

\( \dfrac{x^m}{x^n} = x^{m-n} \)

Example 4: Division

a) \( \dfrac{-x^2}{x} \)

\[ \begin{aligned} \dfrac{\color{red}{-1}\color{blue}{x^2}}{\color{red}{1}\color{blue}{x}} &= \color{red}{\dfrac{-1}{1}} \cdot \color{blue}{\dfrac{x^2}{x}} \\ &= -1 \cdot x^{2-1} \\ &= -x \end{aligned} \]

b) \( \dfrac{-2x^4y^3}{6x^2y^2} \)

\[ \begin{aligned} \dfrac{-2x^4y^3}{6x^2y^2} &= \color{red}{\dfrac{-2}{6}} \cdot \color{blue}{\dfrac{x^4}{x^2}} \cdot \color{green}{\dfrac{y^3}{y^2}} \\ &= -\dfrac{1}{3} \cdot x^{4-2} \cdot y^{3-2} \\ &= -\dfrac{1}{3}x^2y \end{aligned} \]

Practice Questions

Test your skills. Solve the problems below on your own, then click "View Step-by-Step Solutions" to check your work.

  1. Determine the coefficient of each monomial:
    1. \( x^2 \)
    2. \( -2y \)
    3. \( 3xy \)
    4. \( -yx^2 \)
    5. \( yx^3 \)
    6. \( -\dfrac{4}{7}y \)
    7. \( 0.01x^3y \)
    8. \( -\dfrac{xy^3}{4} \)
    View Step-by-Step Solutions
    1. \( x^2 = 1 \cdot x^2 \)  →  Coefficient = 1
    2. \( -2y = -2 \cdot y \)  →  Coefficient = -2
    3. \( 3xy = 3 \cdot xy \)  →  Coefficient = 3
    4. \( -yx^2 = -1 \cdot yx^2 \)  →  Coefficient = -1
    5. \( yx^3 = 1 \cdot yx^3 \)  →  Coefficient = 1
    6. \( -\dfrac{4}{7}y = -\dfrac{4}{7} \cdot y \)  →  Coefficient = \(-\dfrac{4}{7}\)
    7. \( 0.01x^3y = 0.01 \cdot x^3y \)  →  Coefficient = 0.01
    8. \( -\dfrac{xy^3}{4} = -\dfrac{1}{4} \cdot xy^3 \)  →  Coefficient = \(-\dfrac{1}{4}\)
  2. Add and subtract the following monomials:
    1. \( 2x - 4x + 8x \)
    2. \( -x^2 - 7x^2 \)
    3. \( 3xy - xy + 3yx \)
    4. \( x^2y^2 - y^2x^2 \)
    5. \( x - \dfrac{1}{3}x \)
    View Step-by-Step Solutions
    1. \( (2 - 4 + 8)x = \mathbf{6x} \)
    2. \( (-1 - 7)x^2 = \mathbf{-8x^2} \)
    3. \( (3 - 1 + 3)xy = \mathbf{5xy} \)   (Note: \(xy = yx\))
    4. \( (1 - 1)x^2y^2 = 0x^2y^2 = \mathbf{0} \)   (Note: \(x^2y^2 = y^2x^2\))
    5. \( \left(1 - \dfrac{1}{3}\right)x = \left(\dfrac{3}{3} - \dfrac{1}{3}\right)x = \mathbf{\dfrac{2}{3}x} \)
  3. Multiply the following monomials:
    1. \( (-x^2)(-2x) \)
    2. \( (-x^2y)(-y^2x^2) \)
    3. \( \left(-\dfrac{1}{2}x^2\right)(-2x^2) \)
    4. \( (4xy)\left(-\dfrac{3}{4}y^2z\right) \)
    5. \( (-2)\left(-\dfrac{3}{2}x^2y\right) \)
    View Step-by-Step Solutions
    1. \( (-1 \cdot -2)(x^2 \cdot x) = \mathbf{2x^3} \)
    2. \( (-1 \cdot -1)(x^2 \cdot x^2)(y \cdot y^2) = 1 \cdot x^4 \cdot y^3 = \mathbf{x^4y^3} \)
    3. \( \left(-\dfrac{1}{2} \cdot -2\right)(x^2 \cdot x^2) = (1)x^4 = \mathbf{x^4} \)
    4. \( \left(4 \cdot -\dfrac{3}{4}\right)(x)(y \cdot y^2)(z) = \mathbf{-3xy^3z} \)
    5. \( \left(-2 \cdot -\dfrac{3}{2}\right)(x^2y) = \mathbf{3x^2y} \)
  4. Divide the following monomials:
    1. \( \dfrac{x^3}{-x^2} \)
    2. \( \dfrac{-3x^4}{-x^2} \)
    3. \( \dfrac{-5x^3y^3}{15x^2y^2} \)
    4. \( \dfrac{-16x^2y^2z^3}{8x^2y} \)
    5. \( \dfrac{-20xy^2}{-5} \)
    View Step-by-Step Solutions
    1. \( \dfrac{1x^3}{-1x^2} = \left(\dfrac{1}{-1}\right)x^{3-2} = (-1)x^1 = \mathbf{-x} \)
    2. \( \dfrac{-3x^4}{-1x^2} = \left(\dfrac{-3}{-1}\right)x^{4-2} = \mathbf{3x^2} \)
    3. \( \left(\dfrac{-5}{15}\right)\left(\dfrac{x^3}{x^2}\right)\left(\dfrac{y^3}{y^2}\right) = \mathbf{-\dfrac{1}{3}xy} \)
    4. \( \left(\dfrac{-16}{8}\right)\left(\dfrac{x^2}{x^2}\right)\left(\dfrac{y^2}{y}\right)(z^3) = -2(1)(y)(z^3) = \mathbf{-2yz^3} \)
    5. \( \left(\dfrac{-20}{-5}\right)xy^2 = \mathbf{4xy^2} \)
  5. Simplify and write as a single monomial if possible:
    1. \( 9x^2y \cdot \dfrac{y^2}{3x^2} \)
    2. \( x^2y \cdot \dfrac{3x}{x^2} \)
    3. \( \dfrac{y}{3x^2} \cdot x^3 \)
    4. \( \dfrac{x^3}{2y^2} \cdot \dfrac{2xy^3}{x^2} \)
    View Step-by-Step Solutions
    1. \( \dfrac{9x^2y \cdot y^2}{3x^2} = \dfrac{9x^2y^3}{3x^2} = \left(\dfrac{9}{3}\right)\left(\dfrac{x^2}{x^2}\right)(y^3) = \mathbf{3y^3} \)
    2. \( \dfrac{x^2y \cdot 3x}{x^2} = \dfrac{3x^3y}{x^2} = 3\left(\dfrac{x^3}{x^2}\right)y = \mathbf{3xy} \)
    3. \( \dfrac{y \cdot x^3}{3x^2} = \dfrac{x^3y}{3x^2} = \left(\dfrac{1}{3}\right)\left(\dfrac{x^3}{x^2}\right)y = \mathbf{\dfrac{1}{3}xy} \)
    4. \( \dfrac{x^3 \cdot 2xy^3}{2y^2 \cdot x^2} = \dfrac{2x^4y^3}{2x^2y^2} = \left(\dfrac{2}{2}\right)\left(\dfrac{x^4}{x^2}\right)\left(\dfrac{y^3}{y^2}\right) = \mathbf{x^2y} \)

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