Overview
This free calculator computes the real and complex zeros of a polynomial.
Definition. A value \(a\) is a zero of the polynomial \(P(x)\) if and only if \(P(a) = 0\). Equivalently, \((x - a)\) is a factor of \(P(x)\), and \(a\) is an x-intercept of the graph of \(P\) (when \(a\) is real).
Scope. The calculator uses
Algebrite
to find exact roots where possible. For degree ≥ 5, some polynomials have no closed-form expression for
their zeros (by Galois theory), in which case the calculator may return fewer roots or a message.
Interactive Zeros Calculator
Enter the polynomial \(P(x)\) using +, -, *, /, and
^. Include the multiplication operator explicitly (e.g., 2*x^2, not 2x^2).
Input Guide & Sample Polynomials
Use standard operators: + (add), - (subtract), * (multiply),
/ (divide), and ^ (power). Always include the multiplication sign between a
coefficient and a variable.
Sample polynomials to try:
x^2 - 9→ two real roots, \(x = \pm 3\)x^2 + 9→ two complex roots, \(x = \pm 3i\)x^2 + 2*x + 7→ two complex rootsx^3 + 2*x - 3→ one real root and two complex roots3*x^4 - 3→ four complex roots (\(\pm 1\) and \(\pm i\))x^5 + 5*x^4 + 3*x^3 + x^2 - 10*x - 120→ degree 5x^5 + 4*x^4 - 7*x^3 - 28*x^2 + 6*x + 24→ degree 5x^4 - 4*x^3 + 3→ degree 4 (may take a moment)
Worked Example — Find the zeros of \(P(x) = x^2 + 5x - 14\)
Step-by-step solution
Step 1 — Factor the polynomial. Find two numbers that multiply to \(ac = 1 \cdot (-14) = -14\) and add to \(b = 5\). Those numbers are \(7\) and \(-2\).
\[ P(x) = (x - 2)(x + 7) \]Step 2 — Apply the Zero Product Property.
\[ (x - 2)(x + 7) = 0 \implies x - 2 = 0 \text{ or } x + 7 = 0 \]Answer. The zeros are:
\[ x = 2 \quad \text{and} \quad x = -7 \]Check: \(P(2) = 4 + 10 - 14 = 0\) ✓ and \(P(-7) = 49 - 35 - 14 = 0\) ✓
Frequently Asked Questions
What is a zero of a polynomial?
A zero of \(P(x)\) is a value \(a\) for which \(P(a) = 0\). Equivalently, \((x - a)\) is a factor of \(P(x)\), and \(a\) is an x-intercept of the graph of \(P\) (when \(a\) is real).
How many zeros does a polynomial of degree \(n\) have?
By the Fundamental Theorem of Algebra, a nonzero degree-\(n\) polynomial has exactly \(n\) complex zeros, counting multiplicity. Some may be real; the rest come in complex-conjugate pairs.
What is the difference between a zero and an x-intercept?
Every real zero corresponds to an x-intercept of the graph — the point where the graph meets the x-axis at \((a, 0)\). Complex zeros do not appear as x-intercepts on the real Cartesian plane.
Why do some polynomials have no closed-form zero expressions?
By Galois theory, general polynomial equations of degree 5 or higher have no formula in radicals for their roots. Their zeros still exist (by the Fundamental Theorem of Algebra), but they may not be expressible using a finite combination of the four arithmetic operations and radicals.
References and Related Tutorials
- Introduction to Polynomials
- How to Factor Polynomials
- Methods to Find Zeros of Polynomials
- Polynomial Functions, Zeros, Factors, and Intercepts
Sources:
[1] Algebra and Trigonometry — Swokowski, Cole — 1997 — ISBN 0-534-95308-5
[2] Algebra and Trigonometry with Analytic Geometry — Larson, Hostetler, Edwards, Heyd — 1997 — ISBN 0-669-41723-8
Last updated: October 17, 2026