Reducing Rational Expressions: Practice & Solutions
Mastering rational expressions involves two critical steps: factoring the numerator and denominator completely, and dividing out common factors. Detailed solutions are provided below to help you identify common algebraic traps.
Practice Questions
Question 1
For \( x \ne 1 \), simplify: \[ \dfrac{x^2 + 5x - 6}{x - 1} \]
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1. Factor the numerator: \(x^2 + 5x - 6\) becomes \((x - 1)(x + 6)\).
2. The expression is now \(\frac{(x - 1)(x + 6)}{x - 1}\).
3. Since \(x \ne 1\), the term \((x-1)\) is not zero. We can cancel it: \(\mathbf{x + 6}\).
Question 2
Simplify for \( x \ne 5 \): \[ \dfrac{5 - x}{2x - 10} \]
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1. Factor the denominator: \(2x - 10 = 2(x - 5)\).
2. Notice the numerator is \((5 - x)\). This is the opposite of \((x - 5)\).
3. Rewrite the numerator as \(-(x - 5)\).
4. Expression: \(\frac{-(x - 5)}{2(x - 5)}\). Cancel \((x - 5)\) to get \(\mathbf{-1/2}\).
Question 3
For \( x \ne -4 \), simplify: \[ \dfrac{16 - x^2}{x + 4} \]
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1. Factor the numerator as a difference of squares: \(16 - x^2 = (4 - x)(4 + x)\).
2. Expression: \(\frac{(4 - x)(4 + x)}{x + 4}\).
3. Since \((4 + x)\) is the same as \((x + 4)\), they cancel out, leaving \(\mathbf{4 - x}\).
Question 4
Simplify: \[ \dfrac{x + 2}{x^2 + 2x} \]
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1. Factor the denominator: \(x^2 + 2x = x(x + 2)\).
2. Expression: \(\frac{x + 2}{x(x + 2)}\).
3. Cancel the common factor \((x + 2)\) (with condition \(x \ne -2\)).
4. The result is \(\mathbf{1/x}\).
Question 5
For \( x \ne 3 \), simplify: \[ \dfrac{3 - x}{x^2 - x - 6} \]
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1. Factor the denominator: \(x^2 - x - 6 = (x - 3)(x + 2)\).
2. Again, the numerator \((3 - x)\) is the negative of \((x - 3)\).
3. Rewrite numerator as \(-(x - 3)\).
4. Cancel \((x - 3)\) to get \(\mathbf{-1/(x + 2)}\).
Question 6
Simplify: \[ \dfrac{x^3 - x}{x^2 - 1} \]
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1. Factor the numerator: \(x(x^2 - 1)\).
2. Expression: \(\frac{x(x^2 - 1)}{x^2 - 1}\).
3. Cancel the common binomial \((x^2 - 1)\), leaving \(\mathbf{x}\).
Question 7
Simplify: \[ \dfrac{x^2 - 4}{x^2 + 4x - 12} \]
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1. Factor numerator: \((x - 2)(x + 2)\).
2. Factor denominator: \((x - 2)(x + 6)\).
3. Cancel the \((x - 2)\) terms, leaving \(\mathbf{(x + 2)/(x + 6)}\).
Question 8
Simplify: \[ \dfrac{x^2 + 1}{x^3 + x} \]
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1. Factor the denominator: \(x(x^2 + 1)\).
2. Expression: \(\frac{x^2 + 1}{x(x^2 + 1)}\).
3. Cancel the \((x^2 + 1)\) factor, leaving \(\mathbf{1/x}\).
Question 9
Simplify: \[ \dfrac{x^2 + 2x - 3}{2x^2 + 3x - 5} \]
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1. Factor numerator: \((x - 1)(x + 3)\).
2. Factor denominator: \(2x^2 + 3x - 5 = (2x + 5)(x - 1)\).
3. Cancel \((x - 1)\) to get \(\mathbf{(x + 3)/(2x + 5)}\).
Question 10
For \( x \ne 1 \), simplify: \[ \dfrac{x - 1}{(x^2 - 1)(x + 3)} \]
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1. Expand the denominator factor: \(x^2 - 1 = (x - 1)(x + 1)\).
2. Expression: \(\frac{x - 1}{(x - 1)(x + 1)(x + 3)}\).
3. Cancel \((x - 1)\), leaving \(\mathbf{1/((x + 1)(x + 3))}\).