Problem 1: A triangle ABC has angle A = 106 ^{ o}, angle B = 31 ^{ o} and side a = 10 cm. Solve the triangle ABC by finding angle C and sides b and c.(round answers to 1 decimal place).
Solution to Problem 1:

Use the fact that the sum of all three angles of a triangle is equal to 180 ^{ o} to write an equation in C.
A + B + C = 180 ^{ o}

Solve for C.
C = 180 ^{ o}  (A + B) = 43 ^{ o}

Use sine law to write an equation in b.
a / sin(A) = b / sin(B)

Solve for b.
b = a sin (B) / sin(A) = (approximately) 5.4 cm

Use the sine law to write an equation in c.
a / sin(A) = c / sin(C)

Solve for c.
c = a sin (C) / sin(A) = (approximately) 7.1 cm
Problem 2: The angle of elevation to the top C of a building from two points A and B on level ground are 50 degrees and 60 degrees respectively. The distance between points A and B is 30 meters. Points A, B and C are in the same vertical plane. Find the height h of the building(round your answer to the nearest unit).
Solution to Problem 2:

We consider triangle ABC. Angle B internal to triangle ABC is equal to
B = 180^{ o}  60^{ o} = 120^{ o}

In the same triangle, angle C is given by.
C = 180^{ o}  (50^{ o} + 120^{ o}) = 10 ^{ o}

Use sine law to find d.
d / sin(50) = 30 / sin(10)

Solve for d.
d = 30 *sin(50) / sin(10)

We now consider the right triangle.
sin (60) = h / d

Solve for h.
h = d * sin(60)

Substitute d by the expression found above.
h = 30 *sin(50) * sin(60) / sin(10)

Use calculator to approximate h.
h = (approximately) 115 meters.
Problem 3: A triangle ABC has side a = 12 cm, side b = 19 cm and angle A = 80 ^{ o} (angle A is opposite side a). Find side c and angles B and C if possible.(round answers to 1 decimal place).
Solution to Problem 3:

Use sine law to write an equation in sin(B).
a / sin(A) = b / sin(B)

Solve for sin(B).
sin (B) = (b / a) sin(A) = (19/12) sin(80) = (approximately) 1.6

No real angle B satisfies the equation
sin (B) = 1.6

The given problem has no solution.
Problem 4: A triangle ABC has side a = 14 cm, side b = 19 cm and angle A = 32 ^{ o} (angle A is opposite side a). Find side c and angles B and C if possible.(round answers to 1 decimal place).
Solution to Problem 4:

Use sine law to write an equation in sin(B).
a / sin(A) = b / sin(B)

Solve for sin(B).
sin (B) = (b / a) sin(A) = (19/14) sin(32) = (approximately) 0.7192

Two angles satisfy the equation sin (B) = 0.7192 and the given problem has two solutions
B1 = 46.0 ^{ o} and B2 = 134 ^{ o}

Solution 1: Find angle C1 corresponding to B1
C1 = 180  B1  A = 102 ^{ o}

Solution 1: Find side c1 corresponding to C1
c1 / sin(C1) = a / sin(A)
c1 = 14 sin(102) / sin(32) = (approximately) 25.8 cm

Solution 2: Find angle C2 corresponding to B2
C2 = 180  B2  A = 14 ^{ o}

Solution 2: Find side c2 corresponding to C2
c2 / sin(C2) = a / sin(A)
c1 = 14 sin(14) / sin(32) = (approximately) 6.4 cm
Exercises:
1. A triangle ABC has angle A = 104 ^{ o}, angle C = 33 ^{ o} and side c = 9 m. Solve the triangle ABC by finding angle B and sides a and b.(round answers to 1 decimal place).
2. Redo problem 2 with the distance between points A and B equal to 50 meters.
Solutions to above exercises
1. B = 43 ^{ o}, a = 16.0 m , b = 11.3 m
2. 191 meters.
More geometry references
Sine Law Calculator and Solver.
Geometry Tutorials, Problems and Interactive Applets.
Cosine Law Problems.
Cosine Law Calculator and Solver.