七年级指数问题及分步数学解答

想要掌握七年级指数？在本页面，您将找到精心挑选的 数学指数问题及其 详细的分步解答。这些示例将帮助学生理解指数法则，练习化简幂运算，并建立解决指数问题的信心。 非常适合寻求清晰解释和可靠数学练习的学生、家长和教师。

指数问题的详细解答。

  1. 解答
    使用指数的定义。
    1. \(8 \times 8 \times 8 \times 8 = 8^4 \quad \text{(8自乘4次)}\)
    2. \(10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 = 10^7\)
    3. \(A \times A \times A = A^3\)
    4. \(\text{米} \times \text{米} = \text{米}^2\)
    5. \(\text{厘米} \times \text{厘米} \times \text{厘米} = \text{厘米}^3\)
  2. 解答
    利用乘法展开每个幂。
    1. \(2^4 = 2 \times 2 \times 2 \times 2 = 16\)
    2. \(10^4 = 10 \times 10 \times 10 \times 10 = 10{,}000\)
    3. \((-2)^4 = (-2) \times (-2) \times (-2) \times (-2) = 16\)
    4. \(-2^4 = -(2 \times 2 \times 2 \times 2) = -16\)
  3. 解答
    1. \(4 \times 8 = (2 \times 2) \times (2 \times 2 \times 2) = 2^5\)
    2. \(25 \times 5 = (5 \times 5) \times 5 = 5^3\)
    3. \(16 \times 4 \times 4^3 = (4 \times 4) \times 4 \times (4 \times 4 \times 4) = 4^6\)
    4. \(2 \times 2 \times 8 \times 2^3 = 2 \times 2 \times (2 \times 2 \times 2) \times (2 \times 2 \times 2) = 2^8\)
    5. \(B \times B \times B^3 = B \times B \times (B \times B \times B) = B^5\)
  4. 解答
    1. \(2^3 \times 2^4 = (2 \times 2 \times 2) \times (2 \times 2 \times 2 \times 2) = 2^7\)
    2. \(6 \times 6^3 = 6 \times (6 \times 6 \times 6) = 6^4\)
    3. \(5 \times 5^2 \times 5^3 = 5 \times (5 \times 5) \times (5 \times 5 \times 5) = 5^6\)

链接与参考