Applications and Use of the Inverse Functions

Examples on how to apply and use inverse functions in real-life situations and to solve problems in mathematics.


Example 1

Use inverse functions to solve equations.

Solve the following equation:

\[ \log(x - 3) = 2 \]

Solution to Example 1


Example 2

Use inverse functions to find the range of a function.

Find the range of the function \(f\) given by:

\[ f(x) = \frac{2x}{x - 3} \]

Solution to Example 2


Example 3

Use inverse functions to find the angle of elevation.

A camera photographs a hot-air balloon rising vertically. The camera is 300 meters from the launch point. The angle of elevation \(t\) depends on the height \(x\) of the balloon.

(a) Find \(t\) as a function of \(x\).
(b) Find \(t\) when \(x = 150, 300, 600\) meters.
(c) Graph \(t\) as a function of \(x\).

Hot air balloon geometry

Solution to Example 3

xt (degrees)
00
15025.6
30045.0
60063.4
120076.0
300084.3
Graph of angle vs height

Example 4

Use inverse functions to find the radius of a right circular cone.

Five cones of height \(h = 50\) cm have volumes 200, 400, 800, 1600, and 3200 cm\(^3\). Find the radius of each cone.

Solution to Example 4

\[ \begin{aligned} V = 200 &\Rightarrow r = 1.95\text{ cm} \\ V = 400 &\Rightarrow r = 2.76\text{ cm} \\ V = 800 &\Rightarrow r = 3.91\text{ cm} \\ V = 1600 &\Rightarrow r = 5.53\text{ cm} \\ V = 3200 &\Rightarrow r = 7.82\text{ cm} \end{aligned} \]

Example 5

Use inverse functions to solve population growth problems.

\[ P = 200{,}000 e^{0.01t} \]

Find when the population reaches 300,000; 400,000; and 500,000.

Solution to Example 5

\[ \begin{aligned} P = 300{,}000 &\Rightarrow t = 40.55 \text{ years (2041)} \\ P = 400{,}000 &\Rightarrow t = 69.31 \text{ years (2070)} \\ P = 500{,}000 &\Rightarrow t = 91.63 \text{ years (2092)} \end{aligned} \]

More References and Links to Inverse Functions