Solving Equations Using the Distributive Law
This section presents detailed examples and exercises on solving linear equations with parentheses using the distributive property. Solutions include step-by-step reasoning with explanatory notes.
To remove parentheses, apply the distributive law:
Examples with Solutions
Example 1: Solve \( -2(x + 3) = x + 6 \)
- Given: \( -2(x+3)=x+6 \)
- Use the distributive law: \[ -2x - 6 = x + 6 \]
- Add 6 to both sides: \[ -2x - 6 + 6 = x + 6 + 6 \implies -2x = x + 12 \]
- Subtract \(x\) from both sides: \[ -2x - x = 12 \implies -3x = 12 \]
- Divide both sides by \(-3\): \[ x = -4 \]
- Check:
Left side: \( -2(-4+3) = 2 \)
Right side: \( -4 + 6 = 2 \) - Conclusion: \( x = -4 \)
Matched Exercise 1: Solve \( -3(-x+3)=x-7 \)
Example 2: Solve \( -3(-x - 6) = 3x - 23 \)
- Given: \[ -3(-x - 6)=3x - 23 \]
- Apply the distributive law: \[ 3x + 18 = 3x - 23 \]
- Subtract 18 from both sides: \[ 3x = 3x - 41 \]
- Subtract \(3x\) from both sides: \[ 0 = -41 \]
- Conclusion: No real number satisfies the equation. The equation has no solution.
Matched Exercise 2: Solve \( 4(-x + 3) = -4x - 7 \)
Example 3: Solve \( -7(x - 6) - 3x - 3 = 3(x + 5) - 2x \)
- Expand all parentheses: \[ -7x + 42 - 3x - 3 = 3x + 15 - 2x \]
- Group like terms: \[ -10x + 39 = x + 15 \]
- Subtract 39 from both sides: \[ -10x = x - 24 \]
- Subtract \(x\) from both sides: \[ -11x = -24 \]
- Divide by \(-11\): \[ x = \frac{24}{11} \]
- Check: Both sides evaluate to \( \frac{189}{11} \).
- Conclusion: \( x = \frac{24}{11} \)
Matched Exercise 3: Solve \( -5(x - 4) - x + 23 = 5(x - 5) - x \)
Example 4: Solve \( -\,\frac{2(x - 6)}{7} - \frac{x - 3}{2} = -x \)
- Multiply both sides by the LCD \(14\): \[ 14\left[-\frac{2(x - 6)}{7} - \frac{x - 3}{2}\right] = 14(-x) \]
- Simplify: \[ -4(x-6) - 7(x-3) = -14x \]
- Expand and combine terms: \[ -11x + 45 = -14x \]
- Add \(14x\) and subtract 45: \[ 3x = -45 \]
- Divide by 3: \[ x = -15 \]
- Check: Both sides equal 15.
- Conclusion: \( x = -15 \)
Matched Exercise 4: Solve \( -3\,\frac{(x + 4)}{4} - x - 2 = \frac{x - 4}{3} - x \)
Answers to Matched Exercises
- Matched Exercise 1 Answer: \( x = 1 \)
- Matched Exercise 2 Answer: No solution (Identity contradiction: \( 12 = -7 \))
- Matched Exercise 3 Answer: \( x = \frac{34}{5} \) (or \( 6.8 \))
- Matched Exercise 4 Answer: \( x = -\frac{44}{13} \)
Multiple-Choice Practice Questions
Select the correct answer for each question.
Question 1
Solve the equation:
\[-2x + 6 = 4x - 2\]
- a: no solutions
- b: 0
- c: 3
- d: \( \tfrac{1}{2} \)
- e: \( \tfrac{4}{3} \)
Question 2
Solve the equation:
\[-(-x - 5) = x - 2\]
- a: no solutions
- b: -5
- c: 3
- d: \( \tfrac{1}{2} \)
- e: \( \tfrac{4}{3} \)
Question 3
What is the solution to the equation:
\[-(-x - 5) + 5(x - 9) = 2(x + 8) - (2x + 5)\]
- a: 5
- b: no solutions
- c: \( \tfrac{17}{2} \)
- d: \( \tfrac{15}{2} \)
- e: -8
Question 4
Solve the equation:
\[-\dfrac{3x - 1}{3} - \dfrac{2(x - 8)}{5} = \dfrac{x + 8}{5} - 3\]
- a: -10
- b: 15
- c: \( \tfrac{17}{2} \)
- d: \( \tfrac{37}{12} \)
- e: no solutions
Question 5
What is the solution to the equation:
\[\dfrac{2}{7} - \dfrac{x + 8}{4} = \dfrac{3(x - 3)}{5} - \dfrac{3}{2}\]
- a: no solutions
- b: 0
- c: \( \tfrac{17}{111} \)
- d: \( \tfrac{37}{119} \)
- e: \( \tfrac{222}{119} \)
Answers to Multiple-Choice Questions
- Question 1: e
- Question 2: a
- Question 3: c
- Question 4: d
- Question 5: e