Inscribed Circle (Inradius) – Triangle Area, Circle Area, Perimeter & Ratio

Compute inradius r, triangle area At, circle area Ac, circle perimeter (circumference) Pc, and the ratio Ac / At from three sides a, b, c. Decimals allowed, selectable precision.

Triangle with inscribed circle

Key formulas – Inscribed circle

Inradius (from three sides): \[ r = \sqrt{\frac{(s-a)(s-b)(s-c)}{s}},\quad s=\frac{a+b+c}{2}\]

Triangle area (Heron): \[ A_t = \sqrt{s(s-a)(s-b)(s-c)} = r \cdot s \]

Circle area: \[ A_c = \pi r^2 \]    Circle perimeter (circumference): \[ P_c = 2\pi r \]

Ratio: \[ \rho = \frac{A_c}{A_t} \]

Enter positive real numbers, respecting triangle inequality. Choose decimal places for output.

* At = triangle area (Heron); ρ = (circle area) / (triangle area).

Worked example (sides 6, 7, 10) — inradius

\[ s = \frac{6+7+10}{2}=11.5 \]

\[ A_t = \sqrt{11.5(11.5-6)(11.5-7)(11.5-10)} = \sqrt{11.5 \times 5.5 \times 4.5 \times 1.5} = \sqrt{427.6875} \approx 20.680\]

\[ r = \sqrt{\frac{(11.5-6)(11.5-7)(11.5-10)}{11.5}} = \sqrt{\frac{5.5 \times 4.5 \times 1.5}{11.5}} = \sqrt{\frac{37.125}{11.5}} = \sqrt{3.22826} \approx 1.797\]

\[ A_c = \pi r^2 \approx \pi \times 3.229 \approx 10.14,\quad P_c = 2\pi r \approx 11.29\]

\[ \rho = \frac{A_c}{A_t} \approx \frac{10.14}{20.680} \approx 0.490\]

All values shown with 3‑decimal precision by default. Change decimal places above.


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